Linear Transformation: 1. Show that the following maping f are linear: • S : R² → R² defined by f(r, y) = (x + y, æ). • f:R → R defined by f(r, y, z) = 2r – 3y + 4z. • f: R →R defined by f(r, y) = ry. • f: R → R' defined by f(x, y) = (r + 1, 2y, r + y). S:R + R° defined by f(r, y, z) = (\r|, 0). %3D Linear Combination and Span of Vector Space and Sub Space: 2. Show that the ry plane W = (r, y, 0) in R is generated by: (i)u = |2 (ii)u = and v= 3 and 3. Show that that the vector u = -5 is a linear combination of the vectors v = 3 2 and ty = 4. For which value of k the vector u = is a linear combination of the vectors 3 3 and v = of the vectors v = and v = -2 Linearly In-dependency and Dependency 5. Determine whether or not the following vectors i R are linearly dependent: • (1, -2, 1), (2, 1, –1), (7, –4, 1) • (1, 2, –3), (1, –3, 2), (2, –1,5) (1, -3, 7), (2,0, –6), (3, –1, –1), (2, 4, –5) (2, -3, 7), (0,0, 0), (3, –1, -4)
Linear Transformation: 1. Show that the following maping f are linear: • S : R² → R² defined by f(r, y) = (x + y, æ). • f:R → R defined by f(r, y, z) = 2r – 3y + 4z. • f: R →R defined by f(r, y) = ry. • f: R → R' defined by f(x, y) = (r + 1, 2y, r + y). S:R + R° defined by f(r, y, z) = (\r|, 0). %3D Linear Combination and Span of Vector Space and Sub Space: 2. Show that the ry plane W = (r, y, 0) in R is generated by: (i)u = |2 (ii)u = and v= 3 and 3. Show that that the vector u = -5 is a linear combination of the vectors v = 3 2 and ty = 4. For which value of k the vector u = is a linear combination of the vectors 3 3 and v = of the vectors v = and v = -2 Linearly In-dependency and Dependency 5. Determine whether or not the following vectors i R are linearly dependent: • (1, -2, 1), (2, 1, –1), (7, –4, 1) • (1, 2, –3), (1, –3, 2), (2, –1,5) (1, -3, 7), (2,0, –6), (3, –1, –1), (2, 4, –5) (2, -3, 7), (0,0, 0), (3, –1, -4)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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