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linear momentum

linear momentum

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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## Calculating Linear Momentum In this section, we will calculate the magnitude of the linear momentum for various cases. Linear momentum (p) is given by the formula: \[ p = m \cdot v \] where \( m \) is the mass, and \( v \) is the velocity. ### Cases #### (a) A proton with mass \( 1.67 \times 10^{-27} \) kg, moving with a speed of \( 5.65 \times 10^{6} \) m/s \[ \text{Momentum: } \_\_\_\_\_\_\_\_\_\_\_ \text{ kg} \cdot \text{m/s} \] #### (b) A 14.0-g bullet moving with a speed of 470 m/s \[ \text{Momentum: } \_\_\_\_\_\_\_\_\_\_\_ \text{ kg} \cdot \text{m/s} \] #### (c) A 78.0-kg sprinter running with a speed of 12.0 m/s \[ \text{Momentum: } \_\_\_\_\_\_\_\_\_\_\_ \text{ kg} \cdot \text{m/s} \] #### (d) The Earth (mass = \( 5.98 \times 10^{24} \) kg) moving with an orbital speed equal to \( 2.98 \times 10^{4} \) m/s \[ \text{Momentum: } \_\_\_\_\_\_\_\_\_\_\_ \text{ kg} \cdot \text{m/s} \]
Transcribed Image Text:## Calculating Linear Momentum In this section, we will calculate the magnitude of the linear momentum for various cases. Linear momentum (p) is given by the formula: \[ p = m \cdot v \] where \( m \) is the mass, and \( v \) is the velocity. ### Cases #### (a) A proton with mass \( 1.67 \times 10^{-27} \) kg, moving with a speed of \( 5.65 \times 10^{6} \) m/s \[ \text{Momentum: } \_\_\_\_\_\_\_\_\_\_\_ \text{ kg} \cdot \text{m/s} \] #### (b) A 14.0-g bullet moving with a speed of 470 m/s \[ \text{Momentum: } \_\_\_\_\_\_\_\_\_\_\_ \text{ kg} \cdot \text{m/s} \] #### (c) A 78.0-kg sprinter running with a speed of 12.0 m/s \[ \text{Momentum: } \_\_\_\_\_\_\_\_\_\_\_ \text{ kg} \cdot \text{m/s} \] #### (d) The Earth (mass = \( 5.98 \times 10^{24} \) kg) moving with an orbital speed equal to \( 2.98 \times 10^{4} \) m/s \[ \text{Momentum: } \_\_\_\_\_\_\_\_\_\_\_ \text{ kg} \cdot \text{m/s} \]
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