Linear Algebra: A= 7 2 2 4 Need to find P (orthogonal matrix) and D (diagonal matrix) such that A=P*D*PT, PT is transpose matrix of P.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Linear Algebra:

A=

7 2
2 4

Need to find P (orthogonal matrix) and D (diagonal matrix) such that A=P*D*PT, PT is transpose matrix of P.

Found out that D is:

3 0
0 8

the matrix P I calculated was:

2/rad(5) 1/rad(5)
-1/rad(5) 2/rad(5)

But the answer for P was the 2s and 1s switched. I am not sure where I made a mistake, please help. My work is shown attached. 

7.1.15
A=
P=? D-?
A-PDPT
2.
7-1 2
(7-1)(47)-4
22-11a+28-4 oa-11a+24
24-1
7-3 2
2 43
42
EG)=
4 210
420
2/10
4.
-1210
Va
7-82
24-8
-1 2
.
12-4
000
SN
N5
15
P 0 Some
how sunitehel?
D=108
%3D
Answer for P-
房-后
Transcribed Image Text:7.1.15 A= P=? D-? A-PDPT 2. 7-1 2 (7-1)(47)-4 22-11a+28-4 oa-11a+24 24-1 7-3 2 2 43 42 EG)= 4 210 420 2/10 4. -1210 Va 7-82 24-8 -1 2 . 12-4 000 SN N5 15 P 0 Some how sunitehel? D=108 %3D Answer for P- 房-后
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