Line AD is observed in three sections, AB, BC, and CD, with lengths and standard deviations given. Part A If AB 302.97 ± 0.018 ft, BC = 498.67 ± 0.013 ft, and CD = 784.65±0.016 ft, what is the total length AD and its standard deviation? 1586.29 0.016 ft 1586.29 0.047 ft 1586.29 0.217 ft 1586.29 0.027 ft Submit Request Answer Part B If AB 254.061 ± 0.0060 m, BC = 486.578 ± 0.0056 m, CD=465.837 ± 0.0058 m, what is the total length AD and its standard deviation? 1206.476 0.1319 m 1206.476 0.0100 m 1206.476 0.0058 m 1206.476 ± 0.0174 m Submit Request Answer Provide Feedback Next>

Q: Find the distance x in fig below, use the common intensity method as (i= 1200/1+90) x 150 m Sewer 1 Sewer 2 Sewer 3 50 m B Percent Slope Area A 0.44 0.5 B 0.35 2 Sewer D (mm) 1 290 2 410 3 600 0.8 Distance (m) 140 80 d/D 0.3 0.6 V full m/s 1.8 2 1.6

Probable Error - a. b. Example 2 PLANE SURVEYING SU1200 ASSIGNMENT 1 1. The sides of a closed figure have been measured and found to have a total length of 1018.910 m. If the error in the measurement is estimated to be 0.073 m, what is the accuracy ratio of the work? 2. A random error of ± 0.004 m is estimated for each of 22 length measurements (which are to be added together to get the total length). what is the estimated total error? what is the probable total error if the random error is ± 0.006 m per length? 3. A surveying crew or party is capable of taping distances with an estimated probable error of ± 0.005 for each 30.000 m distance. What estimated total error should be expected if a distance of 1400 m is measured? 4. It is desired to tape a distance of 360 m with a total estimated probable error of not more than ± 0.006 m. a. How accurately should 30.000 m distance be measured so that the permissible value is not exceeded? b. How accurately should each 30.000 m distance have…