Lina is doing mathematics tutorial for a summer job. For every tutorial, she charges an initial fee of P500.00 per month, plus a constant fee of P200.00 for each hour of tutorial. 3. Which of the following equation best describes Lina's fee for each of her tutorials? a. fee = 500 + 200x b. fee = 500x + 200 c. fee = 500 - 200x d. fee = 500x – 200 4. Which of the following table best represents Lina's fee for each of her tutorials? a. No of hours 1 2 3 4 Fee 200 | 400 600 800 AS, b. No of hours 1 3 4 Fee 700 | 1200 1700 | 2200 No of hours 1 2 4 C. Fee 700 | 1400 | 2100 | 2800 No of hours 1 2 3 4 d. Fee 700 | 900 1100 1300 5. If Lina spends 15hours on a student and another 13 hours for another student in a month, how NC much will she earn? Write an equation that will suit best the situation. a. fee = [500 - 200(15)] + [500 – 200(13)] b. fee = [500 + 200(15)] + [500 + 200(13)] c. fee = [500(15) + 200] + [500(13) + 20o] d. fee = [500(15) – 200] + [500(13) – 20o]
Lina is doing mathematics tutorial for a summer job. For every tutorial, she charges an initial fee of P500.00 per month, plus a constant fee of P200.00 for each hour of tutorial. 3. Which of the following equation best describes Lina's fee for each of her tutorials? a. fee = 500 + 200x b. fee = 500x + 200 c. fee = 500 - 200x d. fee = 500x – 200 4. Which of the following table best represents Lina's fee for each of her tutorials? a. No of hours 1 2 3 4 Fee 200 | 400 600 800 AS, b. No of hours 1 3 4 Fee 700 | 1200 1700 | 2200 No of hours 1 2 4 C. Fee 700 | 1400 | 2100 | 2800 No of hours 1 2 3 4 d. Fee 700 | 900 1100 1300 5. If Lina spends 15hours on a student and another 13 hours for another student in a month, how NC much will she earn? Write an equation that will suit best the situation. a. fee = [500 - 200(15)] + [500 – 200(13)] b. fee = [500 + 200(15)] + [500 + 200(13)] c. fee = [500(15) + 200] + [500(13) + 20o] d. fee = [500(15) – 200] + [500(13) – 20o]
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![Lina is doing mathematics tutorial for a summer job. For every tutorial, she charges an initial fee of
P500.00 per month, plus a constant fee of P200.00 for each hour of tutorial.
3. Which of the following equation best describes Lina's fee for each of her tutorials?
a. fee = 500 + 200x
b. fee = 500x + 200
C. fee = 500 – 200x
d. fee = 500x – 200
4. Which of the following table best represents Lina's fee for each of her tutorials?
а.
No of hours
1
2
3
4
Fee
200 400
600
800
AS,
1 2
700 | 1200
b.
No of hours
3
4
Fee
| 1700 | 2200
No of hours
1
2
3
4
C.
Fee
700| 1400 | 2100 | 2800
No of hours
d.
1
2
3
4
Fee
700 | 900
1100 | 1300
5. If Lina spends 15hours on a student and another 13 hours for another student in a month, how
much will she earn? Write an equation that will suit best the situation.
a. fee = [500 – 200(15)] + [500 – 200(13)]
b. fee = [500 + 200(15)] + [500 + 200(13)]
c. fee = [500(15) + 200] + [500(13) + 200]
d. fee = [500(15) – 200] + [500(13) – 200]
%3D
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Transcribed Image Text:Lina is doing mathematics tutorial for a summer job. For every tutorial, she charges an initial fee of
P500.00 per month, plus a constant fee of P200.00 for each hour of tutorial.
3. Which of the following equation best describes Lina's fee for each of her tutorials?
a. fee = 500 + 200x
b. fee = 500x + 200
C. fee = 500 – 200x
d. fee = 500x – 200
4. Which of the following table best represents Lina's fee for each of her tutorials?
а.
No of hours
1
2
3
4
Fee
200 400
600
800
AS,
1 2
700 | 1200
b.
No of hours
3
4
Fee
| 1700 | 2200
No of hours
1
2
3
4
C.
Fee
700| 1400 | 2100 | 2800
No of hours
d.
1
2
3
4
Fee
700 | 900
1100 | 1300
5. If Lina spends 15hours on a student and another 13 hours for another student in a month, how
much will she earn? Write an equation that will suit best the situation.
a. fee = [500 – 200(15)] + [500 – 200(13)]
b. fee = [500 + 200(15)] + [500 + 200(13)]
c. fee = [500(15) + 200] + [500(13) + 200]
d. fee = [500(15) – 200] + [500(13) – 200]
%3D
%3D
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