LIMITING REAGENTS TO2/S12 Based on the balanced equation Molar Mass (g/mol) СаН2 + 2H20 - Ca(ОН)2 + 2H2 CаН2 H20 Ca(OH)2 H2 Avogadro's No. 6.022x1023 mol1 42.094 calculate the number of excess reagent units remaining when 38 CaH2 formula units and 68 H20 18.015 molecules react? 74.092 2.016 exact number, no tolerance
LIMITING REAGENTS TO2/S12 Based on the balanced equation Molar Mass (g/mol) СаН2 + 2H20 - Ca(ОН)2 + 2H2 CаН2 H20 Ca(OH)2 H2 Avogadro's No. 6.022x1023 mol1 42.094 calculate the number of excess reagent units remaining when 38 CaH2 formula units and 68 H20 18.015 molecules react? 74.092 2.016 exact number, no tolerance
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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can you solve these 2 and just provide the answer I solved most of the work I just couldnt get the answer right
![LIMITING REAGENTS TO2/S12
Based on the balanced equation
Molar Mass (g/mol)
СаН2 + 2H20 - Ca(ОН)2 + 2H2
CаН2
H20
Ca(OH)2
H2
Avogadro's No.
6.022x1023 mol1
42.094
calculate the number of excess reagent units remaining when 38 CaH2 formula units and 68 H20
18.015
molecules react?
74.092
2.016
exact number, no tolerance](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb53e1d5-de33-4511-8728-0e3815fbd1dc%2Fcd52eb45-2b6e-4df3-b06e-54cb461fd569%2Flpcacqk.png&w=3840&q=75)
Transcribed Image Text:LIMITING REAGENTS TO2/S12
Based on the balanced equation
Molar Mass (g/mol)
СаН2 + 2H20 - Ca(ОН)2 + 2H2
CаН2
H20
Ca(OH)2
H2
Avogadro's No.
6.022x1023 mol1
42.094
calculate the number of excess reagent units remaining when 38 CaH2 formula units and 68 H20
18.015
molecules react?
74.092
2.016
exact number, no tolerance
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