LIMITING REAGENTS T02/S22 Based on the balanced equation Molar Mass (g/mol) 2NBr3 + 3NaoH - N2 + 3NaBr + зновг NB13 253.72 calculate the number of of excess reagent units remaining when 104 NBR3 molecules and 147 NaOH 39.997 NAOH formula units react? N2 28.013 NaBr НOBr Avogadro's No. 6.022x1023 mol"1 102.800 96.911 exact number, no tolerance Question Attempts: 0 of 1 used SUBMIT ANSWER SAVE FOR LATER BASIC STOICHIOMETRY T01/s11 Based on the balanced equation, Molar Mass (g/mol) 10Lİ + N2F4 - 4LİF + 2Lİ3N Li 6.941 calculate the molecules of N,Fa required when 56 formula units of LI3N are formed. N2F4 104.00 LIF 25.939 LizN Avogadro's No. 6.022x1023 mol1 34.830 exact number, no tolerance Question Attempts: 0 of 1 used SUBMIT ANSWER SAVE FOR LATER

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LIMITING REAGENTS T02/S22
Based on the balanced equation
Molar Mass (g/mol)
2NBr3 + 3NaoH - N2 + 3NaBr + зновг
NB13
253.72
calculate the number of of excess reagent units remaining when 104 NBR3 molecules and 147 NaOH
39.997
NAOH
formula units react?
N2
28.013
NaBr
НOBr
Avogadro's No.
6.022x1023 mol"1
102.800
96.911
exact number, no tolerance
Question Attempts: 0 of 1 used
SUBMIT ANSWER
SAVE FOR LATER
Transcribed Image Text:LIMITING REAGENTS T02/S22 Based on the balanced equation Molar Mass (g/mol) 2NBr3 + 3NaoH - N2 + 3NaBr + зновг NB13 253.72 calculate the number of of excess reagent units remaining when 104 NBR3 molecules and 147 NaOH 39.997 NAOH formula units react? N2 28.013 NaBr НOBr Avogadro's No. 6.022x1023 mol"1 102.800 96.911 exact number, no tolerance Question Attempts: 0 of 1 used SUBMIT ANSWER SAVE FOR LATER
BASIC STOICHIOMETRY T01/s11
Based on the balanced equation,
Molar Mass (g/mol)
10Lİ + N2F4 - 4LİF + 2Lİ3N
Li
6.941
calculate the molecules of N,Fa required when 56 formula units of LI3N are formed.
N2F4
104.00
LIF
25.939
LizN
Avogadro's No.
6.022x1023 mol1
34.830
exact number, no tolerance
Question Attempts: 0 of 1 used
SUBMIT ANSWER
SAVE FOR LATER
Transcribed Image Text:BASIC STOICHIOMETRY T01/s11 Based on the balanced equation, Molar Mass (g/mol) 10Lİ + N2F4 - 4LİF + 2Lİ3N Li 6.941 calculate the molecules of N,Fa required when 56 formula units of LI3N are formed. N2F4 104.00 LIF 25.939 LizN Avogadro's No. 6.022x1023 mol1 34.830 exact number, no tolerance Question Attempts: 0 of 1 used SUBMIT ANSWER SAVE FOR LATER
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