lim x→0 3x² - 1 x-1 by L'Hospital's rule we differentiate numerator and and obtain 6x/1 and now substitute x = O. However, if we look at the original function, we see denominator at once that as x approaches 0 the function approaches 1. Why the discrepancy in the answers?
lim x→0 3x² - 1 x-1 by L'Hospital's rule we differentiate numerator and and obtain 6x/1 and now substitute x = O. However, if we look at the original function, we see denominator at once that as x approaches 0 the function approaches 1. Why the discrepancy in the answers?
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:**2. To evaluate**
This text appears to be a section heading on an educational website. There are no graphs or diagrams included with this text. It likely introduces a subsection focused on the topic of evaluation.
![The image presents the following mathematical expression and discussion:
Expression:
\[
\lim_{{x \to 0}} \frac{3x^2 - 1}{x - 1}
\]
Text:
"By L'Hospital's rule, we differentiate the numerator and denominator and obtain \( \frac{6x}{1} \) and now substitute \( x = 0 \). However, if we look at the original function, we see at once that as \( x \) approaches 0, the function approaches 1. Why the discrepancy in the answers?"](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb4ce4869-8ffb-4d6f-acad-72e7a2106c79%2Fc85aab9a-41d9-417f-9dea-f65c9e6d3a9c%2Fuztw1pp_processed.png&w=3840&q=75)
Transcribed Image Text:The image presents the following mathematical expression and discussion:
Expression:
\[
\lim_{{x \to 0}} \frac{3x^2 - 1}{x - 1}
\]
Text:
"By L'Hospital's rule, we differentiate the numerator and denominator and obtain \( \frac{6x}{1} \) and now substitute \( x = 0 \). However, if we look at the original function, we see at once that as \( x \) approaches 0, the function approaches 1. Why the discrepancy in the answers?"
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