lim sin(9x) csc(7x)

Q: limg-0 2x sinx 4-4cosx

A: We can find the limit as below, using L'Hospital rule.

Q: lim Sinx (1-cosX) 2x2

A:

Q: Investigate lim sin

A:

Q: cosx/secx+tanx

A: The given expression is:

Q: ∫xcosx/sin2x

A:

Q: 3 Lim x40 Cosx (2 Cos²x - 1) Cosx -

A:

Q: lim x-0 (cos20x) 7/20x^2

A:

Q: sin 5x lim, X→0

A: Given, limx→ 0sin5xx   Apply the L'Hopital's Rule: limx→ 0sin5xx=limx→ 0cos5x· 51

Q: sin 4x What is lim X-0

A:

Q: Evaluate tan (7x +1) sec³(7x +

A: Given that: ∫tan5(7x+1).sec3(7x+1)dx

Q: Sinx×tanx

A:

Q: an^-1(tan(4))

A: Giventan-1(tan(4))

Q: sinxtanx/cosx+1

A:

Q: sin (9x) sin (3x)

A:

Q: E sin 0 de

A:

Q: sin(4x) g) lim

A:

Q: cotxy5+tanx dx cotx-sinxcosx

A: Since you have asked multiple questions in a single request, we will be answering only the 1st…

Q: 1-secx/tanx - tanx/1-secx

A:

Q: -im sintx- X

A:

Q: find (tanx)

A: The derivative of tanx, ddxtanx=ddxsinxcosx The derivative of tanx using the quotient rule,…

Q: Find y lnxy tan (X+9)

A:

Q: tan 3x lim sin 8x

A:

Q: Sin lim 3xコ スー

A: We have to find limit