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= = lim h→0 -4h = him h(√3-4(a + h) + √√3 - 4a h→0 = (3 - 4a - 4h) - (3 - 4a) h(√3-4(a + h) + √√3 - 4a ed Help? lim h→0 v 3 − 4(a + h) + √3 − 4a 3 - 4a + √√3 – 4a 2√3 - 4a -2 3 - 4a Read It How was the h in the square root extracted?

= = lim h→0 -4h = him h(√3-4(a + h) + √√3 - 4a h→0 = (3 - 4a - 4h) - (3 - 4a) h(√3-4(a + h) + √√3 - 4a ed Help? lim h→0 v 3 − 4(a + h) + √3 − 4a 3 - 4a + √√3 – 4a 2√3 - 4a -2 3 - 4a Read It How was the h in the square root extracted?

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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= lim h→0 11 lim = = lim h→0 eed Help? (3 - 4a - 4h) - (3 - 4a) h(√3 - 4(a + h) + +√3 - 4a -4h h(√3-4(a+h) + √√3 - 4a 3-4(a + h) +√3 - 4a -4 √3-4a+√3 - 4a 2√3 - 4a -2 3 - 4a Read It How was the h in the square root extracted?
Transcribed Image Text:= lim h→0 11 lim = = lim h→0 eed Help? (3 - 4a - 4h) - (3 - 4a) h(√3 - 4(a + h) + +√3 - 4a -4h h(√3-4(a+h) + √√3 - 4a 3-4(a + h) +√3 - 4a -4 √3-4a+√3 - 4a 2√3 - 4a -2 3 - 4a Read It How was the h in the square root extracted?
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