lim b300 مام 3 x (x+2) = 3 (x+2) 3 2 X + -3/1/13 (x+2) A X 3 2 x B (x+2) 1₁. 3 2(x+2) 3 x2 + 2x da (If the integral does not exist, enter 'DNE'.) 3= Ax+2A +Bx→>> 2A=3 A=를 3 In - 1/2²/2 = ³6 ²/2 = ³ 1/1/2018 - A+B=0 +B=0 B = = = 1/2 2(x+2) dim [3 bulal Binize21] - Kim (Bulb), 3h-16-21)-(3-1) = 1x1 3ln1x+21 + = + + 2 b-000 2 4+2 == 3n/x+21 2
lim b300 مام 3 x (x+2) = 3 (x+2) 3 2 X + -3/1/13 (x+2) A X 3 2 x B (x+2) 1₁. 3 2(x+2) 3 x2 + 2x da (If the integral does not exist, enter 'DNE'.) 3= Ax+2A +Bx→>> 2A=3 A=를 3 In - 1/2²/2 = ³6 ²/2 = ³ 1/1/2018 - A+B=0 +B=0 B = = = 1/2 2(x+2) dim [3 bulal Binize21] - Kim (Bulb), 3h-16-21)-(3-1) = 1x1 3ln1x+21 + = + + 2 b-000 2 4+2 == 3n/x+21 2
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![=
lim
boo
3
x (x+2)
dim
مام
ܘܘ ܫ
3
1 x (x+2)
=
3
2
X
+
- 3/1/13
(2+2)
A
X
3
2 x
B
(x+2)
[..
3
2(x+2)
3
x²+2x
da
(If the integral does not exist, enter 'DNE'.)
3= Ax+2A
+ Bx →
2A=3
A=를
3 In
→
- 1/2²/2 = ³6 ÷2 = ³ 1/12) --
A+B=0
+B=0
B=-=-1/1/2
31m11+21
2(x+2)
/ 31nlbl
[3 bulal Binize21] - Lim (Bulb), 3h-16-21)-(3-2) =
1x1
3ln1x+21
+
+
+
2
2
= -
4+2
==
3n/x+21
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ce5a312-47f5-4ea5-9943-a91071c93119%2F3ec37ed6-6b97-4d35-b8fa-629a5eaade13%2F01u4v78_processed.jpeg&w=3840&q=75)
Transcribed Image Text:=
lim
boo
3
x (x+2)
dim
مام
ܘܘ ܫ
3
1 x (x+2)
=
3
2
X
+
- 3/1/13
(2+2)
A
X
3
2 x
B
(x+2)
[..
3
2(x+2)
3
x²+2x
da
(If the integral does not exist, enter 'DNE'.)
3= Ax+2A
+ Bx →
2A=3
A=를
3 In
→
- 1/2²/2 = ³6 ÷2 = ³ 1/12) --
A+B=0
+B=0
B=-=-1/1/2
31m11+21
2(x+2)
/ 31nlbl
[3 bulal Binize21] - Lim (Bulb), 3h-16-21)-(3-2) =
1x1
3ln1x+21
+
+
+
2
2
= -
4+2
==
3n/x+21
2
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