lim 7x + 3. x-2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Problem Statement

2. Evaluate the following limits:

\[ \lim_{x \to -2} 7x + 3. \] 

### Explanation

The expression asks for the evaluation of the limit of the linear function \(7x + 3\) as \(x\) approaches \(-2\). In this context, since \(7x + 3\) is a polynomial function, it is continuous everywhere. Therefore, the limit can be found by direct substitution of \(-2\) into the expression.

### Solution

1. Substitute \(x = -2\) into the equation:
   \[
   7(-2) + 3 = -14 + 3 = -11.
   \]

Therefore, the limit is \(-11\).

### Additional Notes

For linear functions like \(7x + 3\), limits can be evaluated directly by substitution because these functions are continuous across their entire domain. This provides a straightforward and efficient approach to finding limits for polynomial functions.
Transcribed Image Text:### Problem Statement 2. Evaluate the following limits: \[ \lim_{x \to -2} 7x + 3. \] ### Explanation The expression asks for the evaluation of the limit of the linear function \(7x + 3\) as \(x\) approaches \(-2\). In this context, since \(7x + 3\) is a polynomial function, it is continuous everywhere. Therefore, the limit can be found by direct substitution of \(-2\) into the expression. ### Solution 1. Substitute \(x = -2\) into the equation: \[ 7(-2) + 3 = -14 + 3 = -11. \] Therefore, the limit is \(-11\). ### Additional Notes For linear functions like \(7x + 3\), limits can be evaluated directly by substitution because these functions are continuous across their entire domain. This provides a straightforward and efficient approach to finding limits for polynomial functions.
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