lim 4 į (( #)² + ¹); n n

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
icon
Related questions
Question
**14. Sum to integral:**
Evaluate the following limit by identifying the integral that it represents:

\[ \lim_{n \to \infty} \sum_{k=1}^{n} \left( \left( \frac{4k}{n} \right)^5 + 1 \right) \frac{4}{n}. \]

---

**Explanation:**

Given the problem, we notice that the expression \(\frac{4k}{n}\) can be identified as the partition points of the interval \([0, 4]\) as \(n \to \infty\). The expression within the summation therefore represents a Riemann sum. 

To convert this into an integral, observe the following transformation:

1. Identify the function being summed. Let's denote it as \(f(x)\), where \(x = \frac{4k}{n}\). So, \(f(x) = x^5 + 1\).

2. The term \(\frac{4}{n}\) represents the width \(\Delta x\) of each subinterval when the interval \([0, 4]\) is partitioned uniformly into \(n\) subintervals.

Therefore, as \(n \to \infty\),

\[ \sum_{k=1}^{n} \left( \left( \frac{4k}{n} \right)^5 + 1 \right) \frac{4}{n} \]

becomes

\[ \int_{0}^{4} (x^5 + 1) \, dx. \]

So, we evaluate the integral:

\[ \int_{0}^{4} (x^5 + 1) \, dx. \]
Transcribed Image Text:**14. Sum to integral:** Evaluate the following limit by identifying the integral that it represents: \[ \lim_{n \to \infty} \sum_{k=1}^{n} \left( \left( \frac{4k}{n} \right)^5 + 1 \right) \frac{4}{n}. \] --- **Explanation:** Given the problem, we notice that the expression \(\frac{4k}{n}\) can be identified as the partition points of the interval \([0, 4]\) as \(n \to \infty\). The expression within the summation therefore represents a Riemann sum. To convert this into an integral, observe the following transformation: 1. Identify the function being summed. Let's denote it as \(f(x)\), where \(x = \frac{4k}{n}\). So, \(f(x) = x^5 + 1\). 2. The term \(\frac{4}{n}\) represents the width \(\Delta x\) of each subinterval when the interval \([0, 4]\) is partitioned uniformly into \(n\) subintervals. Therefore, as \(n \to \infty\), \[ \sum_{k=1}^{n} \left( \left( \frac{4k}{n} \right)^5 + 1 \right) \frac{4}{n} \] becomes \[ \int_{0}^{4} (x^5 + 1) \, dx. \] So, we evaluate the integral: \[ \int_{0}^{4} (x^5 + 1) \, dx. \]
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning