lim 2 sin(-2 x) 0.3) 4 sin (5 x)

Q: limg-0 2x sinx 4-4cosx

A: We can find the limit as below, using L'Hospital rule.

Q: lim Sinx (1-cosX) 2x2

A:

Q: 1 + tan² dx

A:

Q: S(1 + sinx)-1sinxdx

A:

Q: 8 him XT 2 (secx tanx) 1

A:

Q: 2. sin 2x 1 - sin² x = 2 tan x

A: Aim: To show that sin(2x)1-sin2(x)=2tan(x)

Q: sin 5x lim, X→0

A: Given, limx→ 0sin5xx   Apply the L'Hopital's Rule: limx→ 0sin5xx=limx→ 0cos5x· 51

Q: Evaluate sin dx

A:

Q: Evaluate tan (7x +1) sec³(7x +

A: Given that: ∫tan5(7x+1).sec3(7x+1)dx

Q: x+2 lim sin - x+6x+8 3 2.

A:

Q: 9. Simplify sec² x - 1 sec² x

A: secx=1cosxI=sec2x-1sec2xsin2x+cos2x=1

Q: , 8 tan² (2x) dx

A:

Q: 2- S tan x dx.

A: Given integral is: I=∫0πtan x dx We have to evaluate this integral.

Q: 2r sin 1 (r²) d»

A:

Q: Evaluate sec x dx VIn(sec x + tan x)

A: We will let,  ln( sec x+tan x) = t  to solve this question.

Q: J + tan x)² sec x dx

A:

Q: lim, 0 6 tan² (5x) 15x²

A:

Q: Stan³ x secx dx

A:

Q: 2 X-9 Sinx +34 2

A: Hi ! Thanks for posting your question. Since our portal allows to answer only first three questions,…

Q: Find y lnxy tan (X+9)

A:

Q: Sin lim 3xコ スー

A: We have to find limit

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.