Lillie conducts a hypothesis test and calculates that her sample results have a p-value of .0043, what decision can be made about the null hypothesis? fail to reject the null O Reject the null
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Q: 7.63 0.1587 O 0.0668 O -0.0668 O 0.2 O 0.0062
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- Suppose are running a study/poll about the accuracy rate for fingerprint identification. You randomly sample 74 people and find that 41 of them match the condition you are testing. Suppose you are have the following null and alternative hypotheses for a test you are running: Ho:p = 0.53 Ha:p + 0.53 Calculate the test statistic, rounded to 3 decimal places = ZYou play roulette and observe the ball land in the 1st dozen (i.e., 1-12) 5 times out of 5 spins. You want to perform a test to determine if the wheel is fair. State the null and alternative hypothesis. What is the p-value of this test? For ? α =.05 significance level, what do you conclude?If you use a 0.03 level of significance in a (two-tail) hypothesis test, what is your decision rule for rejecting a null hypothesis that the population mean is 650 if you use the Z test? Which of the following decision rules is correct? A. Reject H0 if −1.88<ZSTAT<+1.88. B. Reject H0 if ZSTAT<−1.88 or ZSTAT>+1.88. C. Reject H0 if ZSTAT<−2.17 or ZSTAT>+2.17. D. Reject H0 if −2.17<ZSTAT<+2.17.
- The smaller the observed p-value, the more evidence you have against the null hypothesis. Select one: True FalseSuppose that in a random selection of 100 colored candies, 24% of them are blue. The candy company claims that the percentage of blue candies is equal to 29%. Use a 0.05 significance level to test that claim. H,: p>0.29 OC. H, p=0.29 H, p#0.29 O D. Ho p+0.29 H, p=0.29 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Fail to reject Ho. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 29% O B. Fail to reject H. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 29% O C. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to…PLEASE ONLY SELECT THE ANSWERS AS SHOWN FOR THE MULTIPLE CHOICE, SUCH AS OPTION 1, 2, ETC. In a study of 796 randomly selected medical malpractice lawsuits, it was found that 489 of them were dropped or dismissed. Use a 0.05 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. Which of the following is the hypothesis test to be conducted? A. H0: p>0.5 H1: p=0.5 B. H0: p<0.5 H1: p=0.5 C. H0: p≠0.5 H1: p=0.5 D. H0: p=0.5 H1: p>0.5 E. H0: p=0.5 H1: p<0.5 F. H0: p=0.5 H1: p≠0.5 What is the test statistic? Z=≠ (Round to two decimal places as needed.) What is the P-value? P-value= (Round to three decimal places as needed.) What is the conclusion about the null hypothesis? Reject the null hypothesis because the P-value is greater than the significance level, α. Reject the null hypothesis because the P-value is less than or equal to the significance level, α. Fail to reject the null hypothesis because the…
- We want to know if students who drank coffee before an exam performed differently on the exam than those who drank water. We matched participants based on their current grades in the class. Our participants’ scores are presented below: Sample 1: drank coffee: 88, 71, 92, 98, 80, 67, 81 Sample 2: drank water: 89, 95, 66, 73, 85, 70, 61 a. What is tobt? b. Can we reject the null hypothesis?The p-value for a hypothesis test turns out to be 0.00956. At a 3% level of significance, what is the proper decision? O Reject Ho O Fail to reject HoSuppose that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 24%. Use a 0.10 significance level to test that claim. H: p>U.24 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Reject Ho- There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 24% O B. Fail to reject Ho. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 24% OC. Fail to reject Hn. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 24% O D. Reject Ho. There is sufficient…
- Use technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the mean is u = 16.00 Mbps. The sample size is n = 20 and the test statistic is t = 1.776.Kelly performs a hypothesis test and calculates a p-value of .489 for her sample data. What decision can be made about the null hypothesis? O fail to reject the null O reject the nullA psychologist specializing counseling claims that, among all married couples, the proportion p for whom her communication program can prevent divorce 79% . In a random sample of 240 married couples who completed her program, 174 of them stayed together. Based on this sample, can we reject the psychologist's claim at the 0.1 level of significance The null hypothesis: H0: ___ The alternative hypothesis: H1: ___ The type of test statistic: (Choose one) ___ The value of the test statistic: (Round to at least three decimal places.) ______ The p-value: (Round to at least three decimal places.) _____ Can we reject psychologist’s claim that the Proportion of married couples for whom her Program can prevent divorce is a least 79%? Yes ____ or NO____