2. Draw a set of light rays which demonstrates why the image of the nail shows up whereit does. Note that the image is ultimately inverted. Hints: First, draw a light ray horizontalfrom the top of the object to the lens; where must this light ray end up? Next, draw a lightray from the top of the object diagonally through the center of the lens; where must thislight ray end up. Finally, draw a light ray from the bottom of the object along the principalaxis; where must this light ray end up?ObjectImage 3. Why can't the image form anywhere else? In other words, what's unique about thatimage's position along the principal axis? Hint: What do all the traced rays do there?

We need to draw the ray diagram

Answered: light ray end up. Finally, draw a light…

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Do question d, e and f.
For each case below draw a ray diagram. Draw the image as an arrow and give a description of the image: (real, virtual or no image formed), (upright or inverted) and (enlarged, reduced or same size). A.) 2F 20 B.) F TAOT
Minimum focal length of your eye Each of your eyes has a lens in it. This lens can change its shape and hence its focal length. By changing the focal length you are able to focus on an object based on how far away it is from you. For this problem you will determine the minimum focal length of your eye. A) Hold an object out in front of you at arm's length. Close one eye and bring the object towards your eye and determine how close it can be to your eye and still be in focus. 25 cm ✓ B.) The average human eye has an image distance of 1.7 cm. In other words, it is 1.7 cm from the lens in your eye to the retina. Using this information and your answer to (A), determine the minimum focal length of your eye. Also determine the magnification for this situation. min 6 x Units are required for this answer. M = 8 X C.) The lens in your eye creates an image. It is this image that the rods and cones in our eye actually detect. Regarding the image your lens created when finding the minimum focal…
At small angles, refraction of light off a spherical surface of radius R between n, // mediums with indices of refraction n1 and nz n2 is given by n2 - n1 Object Image n1 n2 where o is the object's distance from the spherical surface and i is the image's dis- tance, and o is in medium n1 and i is in medium n2. If the spherical surface is curved in the direction depicted in the first diagram, then R> 0. If the surface is curved in the other direction, then R< 0. The sign conventions of o and i are the same as those of the thin lens equation that you're used to. (a) Now consider a thin lens of thick- ness d and index of refraction n surrounded by air (nair both surfaces need not have the same mag- 1). The radii Rị and R2 of nitude. By treating the lens as a combina- tion of two instances of the above equation what does 1 1 equal to? Answer in terms of the n, R1, and R2. Use the approximation that d is negligibly small to solve this problem. (b) The focal length of a lens is defined as…
6. A sheet of glass has an index of refraction nalass = 1.45. Assume that the index of refraction for air is na= 1.00, Light is incident on the sheet of glass at an angle of incidence of 60°, as shown in the figure below. a. Calculate and label the size of each angle (in degrees) on the figure, including angles of incidence and refraction at each of the two parallel surfaces shown. 60 degrees Air na = 1.00 Glass " = 1.45 Air ng = 1.00 b. Calculate the velocity of the light as it travels in the glass.
The side-view mirrors of most cars are convex spherical mirrors (so that the driver can see a wider angle behind the car). Suppose that the side view mirror of your car has a radius of curvature of 18 m, and that another car is 10 m in front of the mirror (behind the car). Ignore any aberration. a) Using the mirror equation to calculate how far the other car appears to be from the mirror. b) Sketch a light ray diagram including the object, the mirror, the image, and the principal light rays. c) Is the image distance smaller or larger than the object distance? Is the image smaller or larger than the object? Answer with calculations.
IP An object is located to the left of a concave lens whose focal length is -41 cm . The magnification produced by the lens is mị = 0.32. Part A To decrease the magnification to m2 = 0.23, should the object be moved closer to the lens or farther away? closer farther away Submit Request Answer Part B Calculate the distance through which the object should be moved. Express your answer using two significant figures. ΑΣφ Ad, = cm Submit Request Answer Provide Feedback |0
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Question 3 Below is a scale drawing of a lens with a focal length f = 15 cm with an object located a distance d, = 20 cm to the left of the lens. The circles mark the locations of the focal points, 15 cm to either side of the lens. In the next activity you will set up an object 20 cm from a 15 cm focal length lens, and locate the position at which the image is formed. Make a ray diagram for this situation, following the steps given in Activity 1.2. Use the ray diagram to determine the distance from the lens to the image that will be formed. Object 1
Fill in the Blanks new TAh original 30° 4.0° -2.5 m- Figure 28-53 Problem 29. Type your answers in all of the blanks and submit Sunlight enters a room at an angle of 30.0° above the horizontal and reflects from a small mirror lying flat on the floor. The reflected light forms a spot on a wall that is 2.50 m behind the mirror (Figure 28-53). You place a notebook under the edge of the mirror nearest to the wall, tilting it upward by 4.00°. How much higher on the wall (Ah) is the spot? Type your answer here cm
Problem 6 Images May Move Faster or Slower An object moves towards a concave mirror at speed up. (a) Show that the speed of the image is: Vo υ (1-2)² where R is the radius of curvature of the mirror. (b) Plot the velocity of the image as a function of the position of the object. Label where the image is real and where it is virtual.
Draw the ray tracing Image. (No numbers needed) just of +he first image the drewing and Final Diverging Diversing lens lens Object

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light ray end up. Finally, draw a light ray from the bottom of the object along the principal axis; where must this light ray end up? Object Image T