Light of wavelengths shorter than 275 nm can be used to photodissociate the hydrogen molecule into hydrogen atoms in the gas phase. A 70.0 mL glass cylinder contains H,(g) at 65.0 mtorr and 25 °C. What minimum amount of light energy must be absorbed by the hydrogen in the tube to dissociate 26.0% of the molecules?
Light of wavelengths shorter than 275 nm can be used to photodissociate the hydrogen molecule into hydrogen atoms in the gas phase. A 70.0 mL glass cylinder contains H,(g) at 65.0 mtorr and 25 °C. What minimum amount of light energy must be absorbed by the hydrogen in the tube to dissociate 26.0% of the molecules?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**Photodissociation of Hydrogen Molecules**
Light of wavelengths shorter than 275 nm can be used to photodissociate the hydrogen molecule into hydrogen atoms in the gas phase. A 70.0 mL glass cylinder contains \( \text{H}_2(g) \) at 65.0 mtorr and 25 °C. What minimum amount of light energy must be absorbed by the hydrogen in the tube to dissociate 26.0% of the molecules?
**Energy Absorbed**: \(\underline{\hspace{3cm}}\) J
**Tools Available**: Scientific notation adjustment tool (×10^y).
This question engages the principles of molecular photodissociation, requiring calculations of energy based on wavelength and gas conditions.
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