Light of wavelengths shorter than 275 nm can be used to photodissociate the hydrogen molecule into hydrogen atoms in the gas phase. A 70.0 mL glass cylinder contains H,(g) at 65.0 mtorr and 25 °C. What minimum amount of light energy must be absorbed by the hydrogen in the tube to dissociate 26.0% of the molecules?

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**Photodissociation of Hydrogen Molecules**

Light of wavelengths shorter than 275 nm can be used to photodissociate the hydrogen molecule into hydrogen atoms in the gas phase. A 70.0 mL glass cylinder contains \( \text{H}_2(g) \) at 65.0 mtorr and 25 °C. What minimum amount of light energy must be absorbed by the hydrogen in the tube to dissociate 26.0% of the molecules?

**Energy Absorbed**: \(\underline{\hspace{3cm}}\) J

**Tools Available**: Scientific notation adjustment tool (×10^y).

This question engages the principles of molecular photodissociation, requiring calculations of energy based on wavelength and gas conditions.
Transcribed Image Text:**Photodissociation of Hydrogen Molecules** Light of wavelengths shorter than 275 nm can be used to photodissociate the hydrogen molecule into hydrogen atoms in the gas phase. A 70.0 mL glass cylinder contains \( \text{H}_2(g) \) at 65.0 mtorr and 25 °C. What minimum amount of light energy must be absorbed by the hydrogen in the tube to dissociate 26.0% of the molecules? **Energy Absorbed**: \(\underline{\hspace{3cm}}\) J **Tools Available**: Scientific notation adjustment tool (×10^y). This question engages the principles of molecular photodissociation, requiring calculations of energy based on wavelength and gas conditions.
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