Light of wavelength λ = 520 nm and intensity I0 = 290 W/m2 is incident upon two narrow slits that are separated by a distance d = 32 μm.  (a)  Write an equation for the cosine of half of the phase difference φ between the waves passing through the two slits in terms of the initial intensity I0 and the resulting intensity I.  (b)  What is the smallest phase angle, φ in radians, for which the resulting intensity of the light will be I = 110 W/m2?  (c)  What is the correct formula for the diffraction angle, θ, relative to the normal in terms of λ, d, I0, and I.  (d)  What is the smallest angle from the normal θ, in radians, for which the resulting intensity of the light will be I = 110 W/m2?

icon
Related questions
Question

 Light of wavelength λ = 520 nm and intensity I0 = 290 W/m2 is incident upon two narrow slits that are separated by a distance d = 32 μm.

 (a)  Write an equation for the cosine of half of the phase difference φ between the waves passing through the two slits in terms of the initial intensity I0 and the resulting intensity I

(b)  What is the smallest phase angle, φ in radians, for which the resulting intensity of the light will be I = 110 W/m2

(c)  What is the correct formula for the diffraction angle, θ, relative to the normal in terms of λdI0, and I

(d)  What is the smallest angle from the normal θ, in radians, for which the resulting intensity of the light will be I = 110 W/m2

Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 4 images

Blurred answer