Light of wavelength 630 nm is incident on a single slit with width 0.400 mm. The figure shows the pattern observed on a screenpositioned 2.00 m from the slit. Determine the distance from the center of the central bright fringe to the second minimum on onemm

Given: The wavelength of the light is 630 nm. The width of the single slit is 0.400 mm. The distance between the slit and the screen is 2.00 m. To determine: The distance from the center of the central bright fringe to the second minimum. In the diagram the distance from the center of the central bright fringe to the second minimum is represented by s. Note: 1 nano meter is equal to 10-9 m. 1 mm is equal to 10-3 m. The formula to calculate the distance of the second minima from center is s=2Dλa where D is the distance between the screen and the slit, λ is the wavelength of the light and a is the width of the slit. Substitute 2.00 m for D, 630×10-9 m for λ and 0.400×10-3 m for a in the above equation, s=2×2.00 m×630×10-9 m0.400×10-3 ms=6300×10-6 ms=0.0063 m The distance from the center of the central bright fringe to the second minimum is 0.0063 m.

Answered: Light of wavelength 630 nm is incident…

Light of wavelength 630 nm is incident on a single slit with width 0.400 mm. The figure shows the pattern observed or positioned 2.00 m from the slit. Determine the distance from the center of the central bright fringe to the second minin