Light of wavelength 5.6x10 10 m from a mercury arc falls upon a metallic photocathode, and the least potential difference applied between the anode and the photocathode to prevent photocurrent is 8.9 V. Calculate the photoelectric threshold for the metal in pm. Answer:

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Chapter1: Units, Trigonometry. And Vectors
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Light of wavelength 5.6×10 1° m from a mercury arc falls upon a metallic
photocathode, and the least potential difference applied between the anode
and the photocathode to prevent photocurrent is 8.9 V. Calculate the
photoelectric threshold for the metal in pm.
Answer:
Transcribed Image Text:Light of wavelength 5.6×10 1° m from a mercury arc falls upon a metallic photocathode, and the least potential difference applied between the anode and the photocathode to prevent photocurrent is 8.9 V. Calculate the photoelectric threshold for the metal in pm. Answer:
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