Light of wavelength 350 nm falls on a potas- sium surface, and the photoelectrons have a maximum kinetic energy of 1.3 eV. What is the work function of potassium? The speed of light is 3 × 10° m/s and Planck's constant is 6.63 × 10' -34 J.s. Answer in units of eV. What is the threshold frequency for potas- sium? Answer in units of Hz.

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A: To find-λ0=?(K.E.)max=?Given-ϕ0=4.2 eV=4.2×1.6×10-19 JVs=3 Vc=3×108 m/sh=6.63×10-34 Jse=1.6×10-19 C

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A: Givenλ=4000 Ao=4000×10-10  mve=6×105 m/sme=9×10-31 Kgc=3×108 m/sh=6.626×10-34 Jsqe=1.6×10-19  JeV-1

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