Light from a laser incident on a platinum plate with a work function of 6.35 eV has half the wavelength obtained in the previous question. It is observed to drive an electron current of 0.15 A. What will be the current, in A, if the laser power is doubled while the wavelength remains half that obtained in the previous question? Answer:
Light from a laser incident on a platinum plate with a work function of 6.35 eV has half the wavelength obtained in the previous question. It is observed to drive an electron current of 0.15 A. What will be the current, in A, if the laser power is doubled while the wavelength remains half that obtained in the previous question? Answer:
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Using the answers provided in the first figure in the fields, please help solve the second question in the figure

Transcribed Image Text:In a photoelectric effect experiment, the stopping potential is observed to drop from
6 V to 2 V when the wavelength of incident light is doubled.
The work function of the irradiated metal is W= 2 eV
The frequency of the light in the original setup is therefore f = 1.93e15
Hz
You should type in large numbers using exponential notation, e.g. enter 1.6 x 10" as
1.бе11

Transcribed Image Text:Light from a laser incident on a platinum plate with a work function of 6.35 eV has
half the wavelength obtained in the previous question. It is observed to drive an
electron current of 0.15 A. What will be the current, in A, if the laser power is
doubled while the wavelength remains half that obtained in the previous question?
Answer:
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