Light bulb 1 operates with a filament temperature of 2400 K, whereas light bulb 2 has a filament temperature of 1800 K. Both filaments have the same emissivity, and both bulbs radiate the same power. Find the ratio A₁/A₂ of the filament areas of the bulbs. A₁/A₂= Number i Units
Energy transfer
The flow of energy from one region to another region is referred to as energy transfer. Since energy is quantitative; it must be transferred to a body or a material to work or to heat the system.
Molar Specific Heat
Heat capacity is the amount of heat energy absorbed or released by a chemical substance per the change in temperature of that substance. The change in heat is also called enthalpy. The SI unit of heat capacity is Joules per Kelvin, which is (J K-1)
Thermal Properties of Matter
Thermal energy is described as one of the form of heat energy which flows from one body of higher temperature to the other with the lower temperature when these two bodies are placed in contact to each other. Heat is described as the form of energy which is transferred between the two systems or in between the systems and their surrounding by the virtue of difference in temperature. Calorimetry is that branch of science which helps in measuring the changes which are taking place in the heat energy of a given body.
![**Problem:**
Light bulb 1 operates with a filament temperature of 2400 K, whereas light bulb 2 has a filament temperature of 1800 K. Both filaments have the same emissivity, and both bulbs radiate the same power. Find the ratio \(A_1/A_2\) of the filament areas of the bulbs.
**Input Fields:**
- **A1/A2 =** [Number input box]
- **Units:** [Dropdown for unit selection]
**Explanation:**
To solve this problem, you can use the Stefan-Boltzmann Law, which relates the power radiated by a black body to its temperature and area. For two light bulbs emitting the same power, the ratio of their areas can be determined using the temperatures given.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd261088c-f753-45e4-ae14-7adbaf3c257c%2F40f80ed9-454e-4dfc-a3fd-2ab4f4e6a295%2Ftbhu3s_processed.png&w=3840&q=75)
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