Lewis model requires: 2000 ft of framing lumber 6000 cubic feet of concrete $4000 for advertising Jefferson model requires: 4000 ft of framing lumber 6000 cubic feet of concrete $6000 for advertising Contracts call for using at least 16000 ft of framing lumber, 36,000 cubic feet of concrete, and $30,000 worth of advertising. If construction cost for each Lewis shed is $40,000, and the construction cost for each Jefferson shed is $30,000, how many of each model should be built to minimize construction costs?
Lewis model requires: 2000 ft of framing lumber 6000 cubic feet of concrete $4000 for advertising Jefferson model requires: 4000 ft of framing lumber 6000 cubic feet of concrete $6000 for advertising Contracts call for using at least 16000 ft of framing lumber, 36,000 cubic feet of concrete, and $30,000 worth of advertising. If construction cost for each Lewis shed is $40,000, and the construction cost for each Jefferson shed is $30,000, how many of each model should be built to minimize construction costs?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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