Let z be a standard normal random variable with mean ? = 0 and standard deviation ? = 1. Use Table 3 in Appendix I to find the probability. (Round your answer to four decimal places.) Between −1.41 and 0.62
Let z be a standard normal random variable with mean ? = 0 and standard deviation ? = 1. Use Table 3 in Appendix I to find the probability. (Round your answer to four decimal places.) Between −1.41 and 0.62
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Let z be a standard normal random variable with mean ? = 0 and standard deviation ? = 1. Use Table 3 in Appendix I to find the probability . (Round your answer to four decimal places.)
Between −1.41 and 0.62
![### Table 3: Areas under the Normal Curve
This table provides the cumulative area under the standard normal distribution curve, corresponding to specific z-scores. It is a reference for determining the probability that a normally distributed random variable will fall within a particular range.
#### Understanding the Table
- **Z-Scores (z):** The leftmost column lists z-scores ranging from -3.4 to 3.4 in increments of 0.1.
- **Columns (.00 to .09):** Each row is followed by 10 columns representing additional increments from .00 to .09.
#### How to Use the Table
1. **Locate the Z-Score:** To find the area under the curve for a specific z-score, first locate the z-score in the leftmost column.
2. **Choose the Decimal Place:** Move across the row to the column that corresponds to the second decimal place of the z-score.
3. **Read the Area:** The intersection of the row and column gives the cumulative probability (area).
#### Example
For a z-score of -1.96:
- Locate -1.9 in the leftmost column.
- Move to the column under .06.
- The table entry is .0250, indicating that the area to the left of z = -1.96 is 0.0250.
#### Applications
This table is widely used in statistics for hypothesis testing, confidence interval calculations, and more. It provides a quick reference to assess probabilities for standard normal distribution events.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff0fdd9be-9990-44a9-8005-60989cbb2f12%2F44fc5d56-577c-43b2-9fd0-cd342bf9bd7b%2F5461iio_processed.png&w=3840&q=75)
Transcribed Image Text:### Table 3: Areas under the Normal Curve
This table provides the cumulative area under the standard normal distribution curve, corresponding to specific z-scores. It is a reference for determining the probability that a normally distributed random variable will fall within a particular range.
#### Understanding the Table
- **Z-Scores (z):** The leftmost column lists z-scores ranging from -3.4 to 3.4 in increments of 0.1.
- **Columns (.00 to .09):** Each row is followed by 10 columns representing additional increments from .00 to .09.
#### How to Use the Table
1. **Locate the Z-Score:** To find the area under the curve for a specific z-score, first locate the z-score in the leftmost column.
2. **Choose the Decimal Place:** Move across the row to the column that corresponds to the second decimal place of the z-score.
3. **Read the Area:** The intersection of the row and column gives the cumulative probability (area).
#### Example
For a z-score of -1.96:
- Locate -1.9 in the leftmost column.
- Move to the column under .06.
- The table entry is .0250, indicating that the area to the left of z = -1.96 is 0.0250.
#### Applications
This table is widely used in statistics for hypothesis testing, confidence interval calculations, and more. It provides a quick reference to assess probabilities for standard normal distribution events.
![This image displays a continuation of Table 3, which is typically a standard normal distribution table or Z-table used in statistics. This type of table provides the cumulative area (probability) from the left up to a specific Z-value in a standard normal distribution (mean of 0, standard deviation of 1).
**Explanation of the Table:**
- **Columns and Rows:**
- The leftmost column represents the Z-value up to the first decimal point (e.g., 0.0, 0.1, 1.0, 2.5).
- The topmost row represents the second decimal place of the Z-value (e.g., .00, .01, .02).
- **Finding a Probability:**
- To find the cumulative probability for a given Z-value, combine the row and column values. For example, for Z = 1.23, locate the row for 1.2 and the column for .03 and find the value at their intersection, which is 0.8907.
- **Table Values:**
- The values in the table are cumulative probabilities, indicating the area under the standard normal curve to the left of a given Z-value.
This table helps in statistical calculations, particularly in hypothesis testing and confidence interval estimation, by allowing users to find probabilities associated with specific Z-values.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff0fdd9be-9990-44a9-8005-60989cbb2f12%2F44fc5d56-577c-43b2-9fd0-cd342bf9bd7b%2Fzjsf18h_processed.png&w=3840&q=75)
Transcribed Image Text:This image displays a continuation of Table 3, which is typically a standard normal distribution table or Z-table used in statistics. This type of table provides the cumulative area (probability) from the left up to a specific Z-value in a standard normal distribution (mean of 0, standard deviation of 1).
**Explanation of the Table:**
- **Columns and Rows:**
- The leftmost column represents the Z-value up to the first decimal point (e.g., 0.0, 0.1, 1.0, 2.5).
- The topmost row represents the second decimal place of the Z-value (e.g., .00, .01, .02).
- **Finding a Probability:**
- To find the cumulative probability for a given Z-value, combine the row and column values. For example, for Z = 1.23, locate the row for 1.2 and the column for .03 and find the value at their intersection, which is 0.8907.
- **Table Values:**
- The values in the table are cumulative probabilities, indicating the area under the standard normal curve to the left of a given Z-value.
This table helps in statistical calculations, particularly in hypothesis testing and confidence interval estimation, by allowing users to find probabilities associated with specific Z-values.
Expert Solution
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Step 1: Introducing the given information
We have given that
Mean( = 0
Standard deviations () = 1
Step by step
Solved in 3 steps with 4 images
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