Let T: R5 → R5 be a linear operator whose characteristic polynomial is pT(x) = (x−3)3(x−5)2. Let V3 and V5 be the eigenspaces associated with eigenvalues 3 and 5, respectively. Judge each item below as true or false. (A) If dimV3 = 3 and dimV5 = 2, then there exists a basis of R5 such that the matrix of T in that basis is
Let T: R5 → R5 be a linear operator whose characteristic polynomial is pT(x) = (x−3)3(x−5)2. Let V3 and V5 be the eigenspaces associated with eigenvalues 3 and 5, respectively. Judge each item below as true or false. (A) If dimV3 = 3 and dimV5 = 2, then there exists a basis of R5 such that the matrix of T in that basis is
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.2: Exponents And Radicals
Problem 46E
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Let T: R5 → R5 be a linear operator whose characteristic polynomial is pT(x) = (x−3)3(x−5)2. Let V3 and V5 be the eigenspaces associated with eigenvalues 3 and 5, respectively. Judge each item below as true or false.
(A) If dimV3 = 3 and dimV5 = 2, then there exists a basis of R5 such that the matrix of T in that basis is
![3
0 0
0 0
3 0
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0 0 5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbc4bcad5-e68d-4caa-90b0-a84e2da87f2d%2F7fb80ece-c3e7-49d9-a377-fe4ebda325ce%2Fhyeqvw_processed.png&w=3840&q=75)
Transcribed Image Text:3
0 0
0 0
3 0
0 3
0 0
5
0 0 5
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