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Let's work through an example to find the power output of a motor. An electric motor is used to run an elevator. The total mass of the elevator car and passenger is 1350 kg. The elevator moves upward a distance of 27.0 m in 15.88 s at a constant speed. What is the power output of the motor during this time? Let's first find the amount of work done. From the mass of the elevator, we can find the weight of the elevator. Because the elevator is moving at a constant speed, the upward force that is applied to the elevator by the motor must be equal to the downward weight. What is the force (in N) on the elevator by the motor? F= x x Think about Newton's second law. Consider the elevator moving upward at a constant speed. What is the acceleration if the speed is constant? What is the net force? If we know the net force, and we know the weight downward, what must be the force upward? N Now, knowing the force, and the distance the elevator moves, we can find the work done by the motor. Remember that work is defined as W = Fd, force times displacement, when the force and displacement are in the same direction. What is the work (in J) by the motor? W = x x Think about how work is related to force. What is the force applied by the motor on the elevator (see the previous step)? What is the displacement of the elevator? Note that both the force and displacement are in the same direction, so the work must be positive. J Finally, from the definition of power above, what is the power output (in W) of the motor? P= X * Think about how power is related to work. What is the work done on the elevator by the motor (see the previous step)? How much time does it take the elevator to move the given distance? W

Let's work through an example to find the power output of a motor. An electric motor is used to run an elevator. The total mass of the elevator car and passenger is 1350 kg. The elevator moves upward a distance of 27.0 m in 15.88 s at a constant speed. What is the power output of the motor during this time? Let's first find the amount of work done. From the mass of the elevator, we can find the weight of the elevator. Because the elevator is moving at a constant speed, the upward force that is applied to the elevator by the motor must be equal to the downward weight. What is the force (in N) on the elevator by the motor? F= x x Think about Newton's second law. Consider the elevator moving upward at a constant speed. What is the acceleration if the speed is constant? What is the net force? If we know the net force, and we know the weight downward, what must be the force upward? N Now, knowing the force, and the distance the elevator moves, we can find the work done by the motor. Remember that work is defined as W = Fd, force times displacement, when the force and displacement are in the same direction. What is the work (in J) by the motor? W = x x Think about how work is related to force. What is the force applied by the motor on the elevator (see the previous step)? What is the displacement of the elevator? Note that both the force and displacement are in the same direction, so the work must be positive. J Finally, from the definition of power above, what is the power output (in W) of the motor? P= X * Think about how power is related to work. What is the work done on the elevator by the motor (see the previous step)? How much time does it take the elevator to move the given distance? W

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Example to Find the Power Output of a Motor** An electric motor is used to run an elevator. The total mass of the elevator car and passenger is 1350 kg. The elevator moves upward a distance of 27.0 m in 15.88 s at a constant speed. What is the power output of the motor during this time? **Step 1: Calculate the Force (F)** Find the amount of work done. From the mass of the elevator, we can find the weight of the elevator. Because the elevator is moving at a constant speed, the upward force that is applied to the elevator by the motor must be equal to the downward weight. Question: What is the force (in N) on the elevator by the motor? Text Box: F = [text box for input] **Hints:** - Think about Newton's second law. Consider the elevator moving upward at a constant speed. - What is the acceleration if the speed is constant? What is the net force? If we know the net force, and we know the weight downward, what must be the force upward? Text Box for Help Icon: [input] N **Step 2: Calculate the Work (W)** Now, knowing the force, and the distance the elevator moves, we can find the work done by the motor. Remember that work is defined as \( W = Fd \), force times displacement, when the force and displacement are in the same direction. Question: What is the work (in J) by the motor? Text Box: W = [text box for input] **Hints:** - Think about how work is related to force. What is the force applied by the motor on the elevator (see the previous step)? - What is the displacement of the elevator? Note: Both the force and displacement are in the same direction, so the work must be positive. Text Box for Help Icon: [input] J **Step 3: Calculate the Power Output (P)** Finally, from the definition of power above, what is the power output (in W) of the motor? Text Box: P = [text box for input] **Hints:** - Think about how power is related to work. What is the work done on the elevator by the motor (see the previous step)? - How much time does it take the elevator to move the given distance? Text Box for Help Icon: [input] W
Transcribed Image Text:**Example to Find the Power Output of a Motor** An electric motor is used to run an elevator. The total mass of the elevator car and passenger is 1350 kg. The elevator moves upward a distance of 27.0 m in 15.88 s at a constant speed. What is the power output of the motor during this time? **Step 1: Calculate the Force (F)** Find the amount of work done. From the mass of the elevator, we can find the weight of the elevator. Because the elevator is moving at a constant speed, the upward force that is applied to the elevator by the motor must be equal to the downward weight. Question: What is the force (in N) on the elevator by the motor? Text Box: F = [text box for input] **Hints:** - Think about Newton's second law. Consider the elevator moving upward at a constant speed. - What is the acceleration if the speed is constant? What is the net force? If we know the net force, and we know the weight downward, what must be the force upward? Text Box for Help Icon: [input] N **Step 2: Calculate the Work (W)** Now, knowing the force, and the distance the elevator moves, we can find the work done by the motor. Remember that work is defined as \( W = Fd \), force times displacement, when the force and displacement are in the same direction. Question: What is the work (in J) by the motor? Text Box: W = [text box for input] **Hints:** - Think about how work is related to force. What is the force applied by the motor on the elevator (see the previous step)? - What is the displacement of the elevator? Note: Both the force and displacement are in the same direction, so the work must be positive. Text Box for Help Icon: [input] J **Step 3: Calculate the Power Output (P)** Finally, from the definition of power above, what is the power output (in W) of the motor? Text Box: P = [text box for input] **Hints:** - Think about how power is related to work. What is the work done on the elevator by the motor (see the previous step)? - How much time does it take the elevator to move the given distance? Text Box for Help Icon: [input] W
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