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Lets' Try! Which data set has a wider spread? a. 2, 3, 3, 4, 5, 6, 8 25th Percentile (Q,) = 3 Semi-interquartile Range = -2)= 1.5 75th Percentile (Q) = 6 2 b. 1, 3, 3, 4, 6, 7, 8, 8 25th Percentile (Q1) = Semi-interquartile Range = 75th Percentile (Q) =

Lets' Try! Which data set has a wider spread? a. 2, 3, 3, 4, 5, 6, 8 25th Percentile (Q,) = 3 Semi-interquartile Range = -2)= 1.5 75th Percentile (Q) = 6 2 b. 1, 3, 3, 4, 6, 7, 8, 8 25th Percentile (Q1) = Semi-interquartile Range = 75th Percentile (Q) =

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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**Let's Try!** **Which data set has a wider spread?** a. 2, 3, 3, 4, 5, 6, 8 - 25th Percentile (\(Q_1\)) = 3 - 75th Percentile (\(Q_3\)) = 6 - Semi-interquartile Range = \(\frac{6 - 3}{2} = 1.5\) b. 1, 3, 3, 4, 6, 7, 8 - 25th Percentile (\(Q_1\)) = ______ - 75th Percentile (\(Q_3\)) = ______ - Semi-interquartile Range = \(\frac{ \: \_ \: - \: \_ \:}{2} = \_\_\_\_\) **Explanation of Diagrams:** There are two boxes that display the calculation of the semi-interquartile range. The values used for \(Q_1\) and \(Q_3\) are substituted into the formula \(\frac{Q_3 - Q_1}{2}\), with the first data set's result given as 1.5. The second data set has placeholders for the calculations.
Transcribed Image Text:**Let's Try!** **Which data set has a wider spread?** a. 2, 3, 3, 4, 5, 6, 8 - 25th Percentile (\(Q_1\)) = 3 - 75th Percentile (\(Q_3\)) = 6 - Semi-interquartile Range = \(\frac{6 - 3}{2} = 1.5\) b. 1, 3, 3, 4, 6, 7, 8 - 25th Percentile (\(Q_1\)) = ______ - 75th Percentile (\(Q_3\)) = ______ - Semi-interquartile Range = \(\frac{ \: \_ \: - \: \_ \:}{2} = \_\_\_\_\) **Explanation of Diagrams:** There are two boxes that display the calculation of the semi-interquartile range. The values used for \(Q_1\) and \(Q_3\) are substituted into the formula \(\frac{Q_3 - Q_1}{2}\), with the first data set's result given as 1.5. The second data set has placeholders for the calculations.
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