Let’s suppose the poppy seeds that she has been eating slowly dilute out of her system by 4% each hour. Let’s further suppose that when the poppy seed level has fallen below 25% in her system, then she will get a “clean test”. Make a properly labelled Excel graph to represent this situation. Make sure the graph is extended far enough to go below the 25% safe level. Suppose she eats a poppy seed muffin at 7am for breakfast. If she has to take her drug test at 3pm the same day, would she pass the test? Explain your reasoning. Suppose she eats poppy seed chicken for dinner at 6pm. Then if her drug test is at 3pm the following day, would she pass the test? Explain your reasoning. If she has a poppy seed muffin at lunch one day (12 noon), what would be the earliest she would be able to take a drug test and pass?

Answered: Let’s suppose the poppy seeds that she…

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Let’s suppose the poppy seeds that she has been eating slowly dilute out of her system by 4% each hour. Let’s further suppose that when the poppy seed level has fallen below 25% in her system, then she will get a “clean test”.

Make a properly labelled Excel graph to represent this situation. Make sure the graph is extended far enough to go below the 25% safe level.

Suppose she eats a poppy seed muffin at 7am for breakfast. If she has to take her drug test at 3pm the same day, would she pass the test? Explain your reasoning.

Suppose she eats poppy seed chicken for dinner at 6pm. Then if her drug test is at 3pm the following day, would she pass the test? Explain your reasoning.

If she has a poppy seed muffin at lunch one day (12 noon), what would be the earliest she would be able to take a drug test and pass?

Expert Solution

Step 1

This question contains multiple sub-parts and no specific part has been asked. So, as per the company's guidelines, only the first three sub-parts will be answered. For other parts, you can ask separately as a new question.

Step 2

Suppose the level of poppy seeds be $y (t)$ .

The initial level of poppy seeds $y_{0}$ is $100$ .

It is given that the level of poppy seeds decreasing $4 %$ after every hour.

$Decrease level = \frac{4}{100} y (t)$ .

Step 3

The level of poppy seeds after an hour from time $(t)$ is shown below:

$\begin{array}{rcl} y (t_{1}) & = & y (t_{0}) - \frac{4}{100} y (t_{0}) \\ = & y (t_{0}) (1 - \frac{4}{100}) \\ = & 0.96 y (t_{0}) \end{array}$

For $y (t_{2})$ ,

$\begin{array}{rcl} y (t_{2}) & = & y (t_{1}) - \frac{4}{100} y (t_{1}) \\ = & y (t_{1}) (1 - 0.04) \\ = & 0.96 y (t_{1}) \end{array}$

For $y (t_{n})$ ,

$y (t_{n}) = 0 . 96^{_{n}} y (t)$

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