Let's solve the logarithmic equation log(3) + log(x – 2) = log(x). = log(x). (a) First, we combine the logarithms on the LHS to get the equivalent equation (b) Next, we use the fact that log is one-to-one to get the equivalent equation = x. (c) Now we find x =

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Let's solve the logarithmic equation
log(3) + log(x – 2) = log(x).
= log(x).
(a) First, we combine the logarithms on the LHS to get the equivalent equation
(b) Next, we use the fact that log is one-to-one to get the equivalent equation
= x.
(c) Now we find x =
Transcribed Image Text:Let's solve the logarithmic equation log(3) + log(x – 2) = log(x). = log(x). (a) First, we combine the logarithms on the LHS to get the equivalent equation (b) Next, we use the fact that log is one-to-one to get the equivalent equation = x. (c) Now we find x =
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