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let's say U= Now (은) = and (11 (2011) (2) udy dt Y = f(t) 114 (0)1) d Mow dflt) dt 412 ||full d flt) - fit) d (11 (1) dt of 11 fet 11² d'(4) Here, d (11F(t)))) dt d() = elt 2 (t). Meltin't) - fit) g(n) dt 11-√(14)112 = dt v du dt A - dflt)/11flt)) flt) +4²14) (11(0)11 - 4(4) ) f(t) 11f (0)|| dt Putting in 1 dly) - 11 fullf'lt) = f(t) f'lt) | 1) - 1 (4) [F(t) 11+(-+)11) वन 11 f(t) 11 ² ||FLEIF(t) - 11 PULP (t) + F(t) P(+) IPHON 11 F(1) 112 (f'lt) x f(t)) x flt) (14/01)³

let's say U= Now (은) = and (11 (2011) (2) udy dt Y = f(t) 114 (0)1) d Mow dflt) dt 412 ||full d flt) - fit) d (11 (1) dt of 11 fet 11² d'(4) Here, d (11F(t)))) dt d() = elt 2 (t). Meltin't) - fit) g(n) dt 11-√(14)112 = dt v du dt A - dflt)/11flt)) flt) +4²14) (11(0)11 - 4(4) ) f(t) 11f (0)|| dt Putting in 1 dly) - 11 fullf'lt) = f(t) f'lt) | 1) - 1 (4) [F(t) 11+(-+)11) वन 11 f(t) 11 ² ||FLEIF(t) - 11 PULP (t) + F(t) P(+) IPHON 11 F(1) 112 (f'lt) x f(t)) x flt) (14/01)³

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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let's say U= Now (은) = and (11 (2011) (2) udy dt Y = f(t) 114 (0)1) d Mow dflt) dt 412 ||full d flt) - fit) d (11 (1) dt of 11 fet 11² d'(4) Here, d (11F(t)))) dt d() = elt 2 (t). Meltin't) - fit) g(n) dt 11-√(14)112 = dt v du dt A - dflt)/11flt)) flt) +4²14) (11(0)11 - 4(4) ) f(t) 11f (0)|| dt Putting in 1 dly) - 11 fullf'lt) = f(t) f'lt) | 1) - 1 (4) [F(t) 11+(-+)11) वन 11 f(t) 11 ² ||FLEIF(t) - 11 PULP (t) + F(t) P(+) IPHON 11 F(1) 112 (f'lt) x f(t)) x flt) (14/01)³
Transcribed Image Text:let's say U= Now (은) = and (11 (2011) (2) udy dt Y = f(t) 114 (0)1) d Mow dflt) dt 412 ||full d flt) - fit) d (11 (1) dt of 11 fet 11² d'(4) Here, d (11F(t)))) dt d() = elt 2 (t). Meltin't) - fit) g(n) dt 11-√(14)112 = dt v du dt A - dflt)/11flt)) flt) +4²14) (11(0)11 - 4(4) ) f(t) 11f (0)|| dt Putting in 1 dly) - 11 fullf'lt) = f(t) f'lt) | 1) - 1 (4) [F(t) 11+(-+)11) वन 11 f(t) 11 ² ||FLEIF(t) - 11 PULP (t) + F(t) P(+) IPHON 11 F(1) 112 (f'lt) x f(t)) x flt) (14/01)³
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