Let's graph y - 2x + 3. Recall that in the general slope-intercept equation y=ma + b, the slope is given by m and the y-intercept is given by b. Therefore, the slope of y = 2a + S is 2 and the y-intercept is (0, 3). In order to graph a line, we need two points on that line. We already know that (0, 3) is on the line. Additionally, because the slope of the line is 2, we know that the point (0+1, 3+2) = (1,5) is also on the line. [How do we know that?] -7 -6 -5 -4 -3 -2 Y 54- 4- 3 (0.3) 1+ -2-- |-4-- -6- (1,5) 1 2 3 4 5 6 7
Let's graph y - 2x + 3. Recall that in the general slope-intercept equation y=ma + b, the slope is given by m and the y-intercept is given by b. Therefore, the slope of y = 2a + S is 2 and the y-intercept is (0, 3). In order to graph a line, we need two points on that line. We already know that (0, 3) is on the line. Additionally, because the slope of the line is 2, we know that the point (0+1, 3+2) = (1,5) is also on the line. [How do we know that?] -7 -6 -5 -4 -3 -2 Y 54- 4- 3 (0.3) 1+ -2-- |-4-- -6- (1,5) 1 2 3 4 5 6 7
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Example is the 2nd image
![Let's graph y = 2x + 3.
Recall that in the general slope-intercept equation y = m + b, the slope is
given by m and the y-intercept is given by b. Therefore, the slope of y = 2x + 3
is 2 and the y-intercept is (0, 3).
In order to graph a line, we need two points on that line. We already know that
(0, 3) is on the line.
Additionally, because the slope of the line is 2, we know that the point
(0+1, 3+2) = (1,5) is also on the line.
[How do we know that?]
-7 -6 -5 -4 -3 -2
Y
4-
3 (0,3)
14
|-4--
-6
(1,5)
1 2 3 4 5 6 7](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff5c26ce1-2eb5-4b23-b3e3-fc93987e911e%2Fe640848d-7719-4b37-9d1d-47b7eaa8b6c6%2Fqi1qoy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Let's graph y = 2x + 3.
Recall that in the general slope-intercept equation y = m + b, the slope is
given by m and the y-intercept is given by b. Therefore, the slope of y = 2x + 3
is 2 and the y-intercept is (0, 3).
In order to graph a line, we need two points on that line. We already know that
(0, 3) is on the line.
Additionally, because the slope of the line is 2, we know that the point
(0+1, 3+2) = (1,5) is also on the line.
[How do we know that?]
-7 -6 -5 -4 -3 -2
Y
4-
3 (0,3)
14
|-4--
-6
(1,5)
1 2 3 4 5 6 7
Transcribed Image Text:I
682997871
⠀⠀
12
20
di do to
T
6
7-8-9-9-2-8-6-
+++
Graph y = 2z - 7.
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