Let's first simplify the equation |2x + b = a by considering two cases: Case 1: 2x + b>0 In this case, 2x + b = 2x + b, so the equation becomes 2x + b = a, which can be rearranged to solve for x as . (1) x = a-b 2 ***..... Case 2: 2x + b < 0 In this case, 2x + b = - (2x + b), - (2x + b) = a, which can be rearranged to solve for x as x = so the equation becomes : b-a 2 (2) ? Why don't, X = -a-b 2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Compare the two image i send, please calculate the true answer. why -(2x+b)=a,  can to be x = b-a/2 in cases 2. I mark the problem with red color. This complete question thank u

on the previous Question me In bartleby, the expert Solve
the two ase from equation. But after I write again,
In the case 2 me and the expert is different.
This
Colte
from
Case
me
12xth1 = a
Case 1
2xtb 2 a
2xtb = a
x = a-b
2
Case 2
1
2x tb co
= (2xth) = 9
- 2x - b = a
X 2
atb
.-2
x = -a-b
-a-b
J
with
this different from the expert,
How, Case is true In Case 2
i case
Transcribed Image Text:on the previous Question me In bartleby, the expert Solve the two ase from equation. But after I write again, In the case 2 me and the expert is different. This Colte from Case me 12xth1 = a Case 1 2xtb 2 a 2xtb = a x = a-b 2 Case 2 1 2x tb co = (2xth) = 9 - 2x - b = a X 2 atb .-2 x = -a-b -a-b J with this different from the expert, How, Case is true In Case 2 i case
Let's first simplify the equation |2x + b =
Case 1: 2x + b>0
In this case, 2x + b = 2x + b,
so the equation becomes 2x + b = a,
which can be rearranged to solve for x as
X =
a-b
2
(1)
...
Case 2: 2x + b < 0
In this case, 2x + b =
= a by considering two cases:
(2x + b),
- (2x + b) = a,
so the equation becomes :
which can be rearranged to solve for x as
X =
b-a
2
. (2) 2
0
Why don't, x=-a-b
Transcribed Image Text:Let's first simplify the equation |2x + b = Case 1: 2x + b>0 In this case, 2x + b = 2x + b, so the equation becomes 2x + b = a, which can be rearranged to solve for x as X = a-b 2 (1) ... Case 2: 2x + b < 0 In this case, 2x + b = = a by considering two cases: (2x + b), - (2x + b) = a, so the equation becomes : which can be rearranged to solve for x as X = b-a 2 . (2) 2 0 Why don't, x=-a-b
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