Let's consider a simple supported beam subjected to a triangular distributed load and a couple moment as shown in the figure below. The equation of the shear force (0 ≤ x ≤ 2m) is given by: Select one: OV (x) = -100 X² -66.7 (N) O V(x) = -200 x²-133.3 (N) O V(x) = -25 X² +8.3 (N) O V(x) = -125 X² +41.7 (N) O V(x) = -75 x² +25 (N) 2m 300 N/m 150 N.m

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Let's consider a simple supported beam subjected to a triangular distributed load and a couple moment as shown in the figure below.
The equation of the shear force (0 ≤x≤ 2m) is given by:
Select one:
O V(x) = -100 X² -66.7 (N)
O V(x) = -200 x²-133.3 (N)
O V(x) = -25 X² +8.3 (N)
O V(x) = -125 x² +41.7 (N)
O V(x) = -75 x² +25 (N)
2m
300 N/m
150 N.m
Transcribed Image Text:Let's consider a simple supported beam subjected to a triangular distributed load and a couple moment as shown in the figure below. The equation of the shear force (0 ≤x≤ 2m) is given by: Select one: O V(x) = -100 X² -66.7 (N) O V(x) = -200 x²-133.3 (N) O V(x) = -25 X² +8.3 (N) O V(x) = -125 x² +41.7 (N) O V(x) = -75 x² +25 (N) 2m 300 N/m 150 N.m
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