Let's assume that your sample mean and sample standard deviation are the true population mean and standard deviation, compute for the following probabilities C. P[X > 2650] Z-score: 2.78 P[Za]= 0.0027
Let's assume that your sample mean and sample standard deviation are the true population mean and standard deviation, compute for the following probabilities C. P[X > 2650] Z-score: 2.78 P[Za]= 0.0027
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 12PPS
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![Let's assume that your sample mean and sample standard deviation are the true
population mean and standard deviation, compute for the following probabilities
C. P[X > 2650]
Z-score: 2.78
P[Z<a]= 0.9973
P[Z>a]= 0.0027](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc0f739d1-1cdf-4b2c-a42a-39d4115dc412%2F20a51c61-f434-4f8d-bc6d-4270013501b0%2Fqmykf0s_processed.png&w=3840&q=75)
Transcribed Image Text:Let's assume that your sample mean and sample standard deviation are the true
population mean and standard deviation, compute for the following probabilities
C. P[X > 2650]
Z-score: 2.78
P[Z<a]= 0.9973
P[Z>a]= 0.0027
![For MEMBER 5: The number of demons slayed by the demon slayers per three years
is known to be normally distributed with an average of 2560 and a standard deviation
of 1419.
The mean and standard deviation of the sample mean is given by
Mean= µz = µ= 2560
Standard deviation(og) = 0/Vn= 1419/v5
=634.60
Standard deviation(oz) = 634.60](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc0f739d1-1cdf-4b2c-a42a-39d4115dc412%2F20a51c61-f434-4f8d-bc6d-4270013501b0%2Fcgt0srm_processed.png&w=3840&q=75)
Transcribed Image Text:For MEMBER 5: The number of demons slayed by the demon slayers per three years
is known to be normally distributed with an average of 2560 and a standard deviation
of 1419.
The mean and standard deviation of the sample mean is given by
Mean= µz = µ= 2560
Standard deviation(og) = 0/Vn= 1419/v5
=634.60
Standard deviation(oz) = 634.60
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