Let E, F and G be three events in S with P(E) = 0.43, P(F) = 0.61, P(G) = 0.58, P(E ∩ F) = 0.29, P(E ∩ G) = 0.24, P(F ∩ G) = 0.45, and P(E ∩ F ∩ G) = 0.19. Find P(EC ∪ FC ∪ GC). P(EC ∪ FC ∪ GC) =

Let E, F and G be three events in S with P(E) = 0.43, P(F) = 0.61, P(G) = 0.58, P(E ∩ F) = 0.29, P(E ∩ G) = 0.24, P(F ∩ G) = 0.45, and P(E ∩ F ∩ G) = 0.19. Find P(EC ∪ FC ∪ GC). P(EC ∪ FC ∪ GC) =

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

Let E, F and G be three events in S with P(E) = 0.43, P(F) = 0.61, P(G) = 0.58, P(E ∩ F) = 0.29, P(E ∩ G) = 0.24, P(F ∩ G) = 0.45, and P(E ∩ F ∩ G) = 0.19. Find P(E^C ∪ F^C ∪ G^C).
P(E^C ∪ F^C ∪ G^C) =

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