Let E, F and G be three events in S with P(E) = 0.36, P(F) = 0.47, P(G) = 0.45, P(E ∩ F) = 0.13, P(E ∩ G) = 0.18, P(F ∩ G) = 0.28, and P(E ∩ F ∩ G) = 0.08. Find P(EC ∩ F ∩ G), P(E ∩ FC ∩ G), and P(E ∩ F ∩ GC). P(EC ∩ F ∩ G) P(E ∩ FC ∩ G) P(E ∩ F ∩ GC)

Let E, F and G be three events in S with P(E) = 0.36, P(F) = 0.47, P(G) = 0.45, P(E ∩ F) = 0.13, P(E ∩ G) = 0.18, P(F ∩ G) = 0.28, and P(E ∩ F ∩ G) = 0.08. Find P(EC ∩ F ∩ G), P(E ∩ FC ∩ G), and P(E ∩ F ∩ GC). P(EC ∩ F ∩ G) P(E ∩ FC ∩ G) P(E ∩ F ∩ GC)

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

Let E, F and G be three events in S with P(E) = 0.36, P(F) = 0.47, P(G) = 0.45, P(E ∩ F) = 0.13, P(E ∩ G) = 0.18, P(F ∩ G) = 0.28, and P(E ∩ F ∩ G) = 0.08. Find P(E^C ∩ F ∩ G), P(E ∩ F^C ∩ G), and P(E ∩ F ∩ G^C).

P(E^C ∩ F ∩ G)
P(E ∩ F^C ∩ G)
P(E ∩ F ∩ G^C)

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