Let z(x, y) Calculate дz მs дz 2t = дz მs & 7х2 + y² where x = s + 8t & y = дz St by first finding ?х ду дх 3 ?s' is t 1 & - 78 + 9t. ду St and using the chain rule.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Let \( z(x, y) = -7x^2 + y^2 \) where \( x = s + 8t \) and \( y = -7s + 9t \).

Calculate \(\frac{\partial z}{\partial s}\) and \(\frac{\partial z}{\partial t}\) by first finding \(\frac{\partial x}{\partial s}\), \(\frac{\partial y}{\partial s}\), \(\frac{\partial x}{\partial t}\), and \(\frac{\partial y}{\partial t}\) and using the chain rule.

\[
\frac{\partial z}{\partial s} = \underline{\hspace{6cm}}
\]

\[
\frac{\partial z}{\partial t} = \underline{\hspace{6cm}}
\]
Transcribed Image Text:Let \( z(x, y) = -7x^2 + y^2 \) where \( x = s + 8t \) and \( y = -7s + 9t \). Calculate \(\frac{\partial z}{\partial s}\) and \(\frac{\partial z}{\partial t}\) by first finding \(\frac{\partial x}{\partial s}\), \(\frac{\partial y}{\partial s}\), \(\frac{\partial x}{\partial t}\), and \(\frac{\partial y}{\partial t}\) and using the chain rule. \[ \frac{\partial z}{\partial s} = \underline{\hspace{6cm}} \] \[ \frac{\partial z}{\partial t} = \underline{\hspace{6cm}} \]
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