Let z = F(x , y), where x = u ev - 4 and y = ut e -V + 3. Use the chain rule %3D az to find du at (u , v) = (1 , 0) given that Fx(1 , 0) = 13 , F,(1 , 0 )) = - 2, %3D Fx(- 3, 4)) = 4 and Fy(- 3, 4) = - 11. Enter an integer or a fully reduced fraction such as -2,0, 15, 3/4 , -7/9 , etc. No Spaces Please.

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