Let z be a standard normal variable. Let x be a normal random variable with mean µx = 12 and standard deviation σx = 4. For parts (a) and (b), (i) sketch the probability distribution and shade the area corresponding to the probability and (ii) calculate the probability. Make sure your sketches are neat and well-labeled. (a) P(z ≤ 2.37) (b) P(6.28 ≤ x ≤ 17.72) (c) Now, find the upper bound on the lower 12% of z.
Let z be a standard normal variable. Let x be a normal random variable with
Since you have posted a question with multiple sub-parts, we will solve first three sub-
parts for you. To get remaining sub-part solved please repost the complete question and
mention the sub-parts to be solved
From the information, given that
Let X denotes the random variable which follows normal distribution with the mean of 12 and the standard deviation of 4.
That is,
µ=12
σ= 4.
Step by step
Solved in 5 steps with 8 images
