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Let y(x) be the solution for the DE. y' + y tan (x) + sin(x) JT If y(0) = In 2, then at x = 4 the value of y is 3 In 2 2/2 In 2 2/2 In 2 2/2 (1 - ) 2 In 2 12 3 In 2

Let y(x) be the solution for the DE. y' + y tan (x) + sin(x) JT If y(0) = In 2, then at x = 4 the value of y is 3 In 2 2/2 In 2 2/2 In 2 2/2 (1 - ) 2 In 2 12 3 In 2

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Let y(x) be the solution for the DE. y' + y tan(x) + sin(x) = 0 JT If y(0) = In 2, then at x = 4 the value of y is 3 In 2 2/2 In 2 2 12 In 2 - 2 /2 (주-1)루 ㅇ 2 In 2 2 3 In 2 2/2
Transcribed Image Text:Let y(x) be the solution for the DE. y' + y tan(x) + sin(x) = 0 JT If y(0) = In 2, then at x = 4 the value of y is 3 In 2 2/2 In 2 2 12 In 2 - 2 /2 (주-1)루 ㅇ 2 In 2 2 3 In 2 2/2
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