Let Y(t)= X(t) be the solution of , ly(t). 6 - 1 Y' = -2 Y, Y(0) = 8 5 4 Write y(T/10), round your answer to two digits after the decimal sign.

Q: dx 5x. J 75V9x² – 1

A:

Q: y = 2x – 6x + 10 — у" — ху" — 2y' %3D — 24х?

A: Given: y=2x3-6x+10

Q: x3-2x2y+3xy2+y3-22=0             find dy/dx

A: In order to find the derivative of equations we have to differentiate implicitly .

Q: for

A:

Q: Solve 2- (2xy - 2y)dx + (3x'y-4x)dy 0

A: We have to solve given problem:

Q: SOLVE FOR CL is constant : A² jª (a²-2₁²x² + x²) dx = 1

A: The given integral is A2∫-aaa4-2a2x2+x4dx=1. We have to find the value of a.

Q: Q9. Solve (x3 + уз)dy + x2y dх %3D0

A:

Q: x2 - 4 3 dx

A: The given integral is: I=∫x2-4x3dx

Q: dx XI. Vx(x+1)

A: Here I am attaching image so that you understand each and every step.

Q: xdy = (y - Vx² + y²) dx

A:

Q: r4 3 +1 d y? 1

A: We will solve the problem

Q: Q2: find y' y= 33xelnx²

A: We have the given function : y=33xelnx2 We have to find the derivative of this function.

Q: Find the derivative y=-4x 7 2x + √3 -

A:

Q: (3x*-5)(2x +9x-6 of y= dy and %3D Determine the 7x

A: Simplify the equation. y=6x7-10x3+27x5-45x-18x4+307x5=67x2-107·1x2+277-457·1x4-187·1x+307·1x5

Q: Find when y = -5 (In(x))¯4

A: Explanation of the answer is as follows

Q: Solve (3x*y? – x²)dy + (4x³y3 - 2xy)dx 0 %3D | | .3

A: Given differential equation is exact differential equation. We solve it as follows:

Q: let y = -3 x¹-2x, find y' -12 x4-2 -12 x³ -2 Onone of these answers O-4x³ - 2

A: Given: y=-3x4-2x

Q: Find // (3x + 5y)dA where D D = {(x, y) | x² + y² 0} . Round your answer to four decimal places.

A: Double integration

Q: 5. Determine the average value of f(x) over the interval from x = a to x = b, where a) f (x) = x²; a…

A:

Q: (хе* + 4e* + 4eУ + 4lny) dx + ( хеУ + — dy %3D0;B у (0) — 0

A:

Q: xy2 = 8 at (2,2)

A: Substitute x=2 and y=2 in the given function xy2

Q: 2. (D2 + 3D)y = -18x: v = 0. Dy = 5 when x = 0

A: Given differential equation is  D2+3Dy=-18x  and the given conditions are y=0, Dy=5 when x=0 find…

Q: Solve for y. P(0)=(-12/37, y), P(0) is in Ql

A: Given P(θ)=-1237, y and P(θ) is in Quadrant 2.

Q: on(1-y)csc²( y) dy

A: This question can be solved using the concept of integration by substitution.

Q: nd / (2x° + 7x°) dx

A: