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Let y(t) represent the number of ripe berries on a bush at a given time t. New berries ripen on the bush at a rate proportional to the amount of ripe berries currently on the bush. Additionally, a farmer harvests ripe berries from the bush at a constant rate of b berries per day. Which differential equation below best models this situation? Select one: dy а. ky dt dy b. = k(y + b) dt dy С. dt = ky – b dy d. = k(y – b) dt dy е. dt = ky – bt

Let y(t) represent the number of ripe berries on a bush at a given time t. New berries ripen on the bush at a rate proportional to the amount of ripe berries currently on the bush. Additionally, a farmer harvests ripe berries from the bush at a constant rate of b berries per day. Which differential equation below best models this situation? Select one: dy а. ky dt dy b. = k(y + b) dt dy С. dt = ky – b dy d. = k(y – b) dt dy е. dt = ky – bt

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Let y(t) represent the number of ripe berries on a bush at a given time t. New berries ripen on the bush at a rate proportional to the amount of ripe berries currently on the bush. Additionally, a farmer harvests ripe berries from the bush at a constant rate of b berries per day. Which differential equation below best models this situation? Select one: dy а. ky dt dy b. = k(y + b) dt dy С. dt = ky – b dy d. = k(y – b) dt dy е. dt = ky – bt
Transcribed Image Text:Let y(t) represent the number of ripe berries on a bush at a given time t. New berries ripen on the bush at a rate proportional to the amount of ripe berries currently on the bush. Additionally, a farmer harvests ripe berries from the bush at a constant rate of b berries per day. Which differential equation below best models this situation? Select one: dy а. ky dt dy b. = k(y + b) dt dy С. dt = ky – b dy d. = k(y – b) dt dy е. dt = ky – bt
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