Let y= E a, (x – 1)" be the power series solution to n=0 у - 7у +11x3%0, у(1)— 4. Find ag. 269 a3 3 268 az = 3 271 az = 3
Let y= E a, (x – 1)" be the power series solution to n=0 у - 7у +11x3%0, у(1)— 4. Find ag. 269 a3 3 268 az = 3 271 az = 3
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 9T
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Question
![Let y= 2 a, (x- 1)" be the power series solution to
n=0
У — 7у+11x3%-0, у(1) %— 4. Find az-
269
az =
3
268
az =
3
271
a3 =
3
None
az = 89](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8615e4ee-aac8-487e-9b68-fc16837d7fd6%2F1bc1913a-128b-4365-84ac-6645ca5bff25%2F7fsibfh_processed.png&w=3840&q=75)
Transcribed Image Text:Let y= 2 a, (x- 1)" be the power series solution to
n=0
У — 7у+11x3%-0, у(1) %— 4. Find az-
269
az =
3
268
az =
3
271
a3 =
3
None
az = 89
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