Let y denote the number of broken eggs in a randomly selected carton of one dozen eggs. Suppose that the probability distribution of y is as follows. y 1 3 4 p(y) 0.55 0.24 0.13 0.05 (a) Only y values of 0, 1, 2, 3, and 4 have positive probabilities. What is p(4)? (Hint: Consider the properties of a discrete probability distribution.) (b) How would you interpret p(1) = 0.24? (c) Calculate P(y s 2), the probability that the carton contains at most two broken eggs. Interpret this probability. (d) Calculate P(y < 2), the probability that the carton contains fewer than two broken eggs. Why is this smaller than the probability in part (c)?
Let y denote the number of broken eggs in a randomly selected carton of one dozen eggs. Suppose that the probability distribution of y is as follows. y 1 3 4 p(y) 0.55 0.24 0.13 0.05 (a) Only y values of 0, 1, 2, 3, and 4 have positive probabilities. What is p(4)? (Hint: Consider the properties of a discrete probability distribution.) (b) How would you interpret p(1) = 0.24? (c) Calculate P(y s 2), the probability that the carton contains at most two broken eggs. Interpret this probability. (d) Calculate P(y < 2), the probability that the carton contains fewer than two broken eggs. Why is this smaller than the probability in part (c)?
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
Related questions
Question
Please answer part b,c, and d
![Let y denote the number of broken eggs in a randomly selected carton of one dozen eggs. Suppose that the probability distribution of y is as follows.
1
3
4
p(y)
0.55
0.24
0.13
0.05
(a) Only y values of 0, 1, 2, 3, and 4 have positive probabilities. What is p(4)? (Hint: Consider the properties of a discrete probability distribution.)
(b) How would you interpret p(1) = 0.24?
(c) Calculate P(y < 2), the probability that the carton contains at most two broken eggs.
Interpret this probability.
(d) Calculate P(y < 2), the probability that the carton contains fewer than two broken eggs.
Why is this smaller than the probability in part (c)?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F32b454a5-c02e-43eb-8be8-50e41b1b60c2%2F58ec7711-6537-4987-9d71-318f5539f5b9%2F535guds_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Let y denote the number of broken eggs in a randomly selected carton of one dozen eggs. Suppose that the probability distribution of y is as follows.
1
3
4
p(y)
0.55
0.24
0.13
0.05
(a) Only y values of 0, 1, 2, 3, and 4 have positive probabilities. What is p(4)? (Hint: Consider the properties of a discrete probability distribution.)
(b) How would you interpret p(1) = 0.24?
(c) Calculate P(y < 2), the probability that the carton contains at most two broken eggs.
Interpret this probability.
(d) Calculate P(y < 2), the probability that the carton contains fewer than two broken eggs.
Why is this smaller than the probability in part (c)?
![(b) How would you interpret p(1) = 0.24?
The probability distribution of a discrete random variable y gives the probability associated with each possible y value. Each probability is the long run relative frequency of occurrence of the corresponding
y value when a chance experiment is performed a very large number of times. The notation p(1) represents the probability that the random variable y takes on the value 1.
Thus, p(1) = 0.24 indicates the following.
O In the long run, the proportion that will have at most one broken egg will equal 0.24.
O The proportion of eggs that will be broken in each carton from this population is 0.24.
O The probability of one randomly chosen carton having broken eggs in it is 0.24.
O In the long run, the proportion of cartons that have exactly one broken egg will equal 0.24.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F32b454a5-c02e-43eb-8be8-50e41b1b60c2%2F58ec7711-6537-4987-9d71-318f5539f5b9%2Fiqd8qv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(b) How would you interpret p(1) = 0.24?
The probability distribution of a discrete random variable y gives the probability associated with each possible y value. Each probability is the long run relative frequency of occurrence of the corresponding
y value when a chance experiment is performed a very large number of times. The notation p(1) represents the probability that the random variable y takes on the value 1.
Thus, p(1) = 0.24 indicates the following.
O In the long run, the proportion that will have at most one broken egg will equal 0.24.
O The proportion of eggs that will be broken in each carton from this population is 0.24.
O The probability of one randomly chosen carton having broken eggs in it is 0.24.
O In the long run, the proportion of cartons that have exactly one broken egg will equal 0.24.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
Recommended textbooks for you
![A First Course in Probability (10th Edition)](https://www.bartleby.com/isbn_cover_images/9780134753119/9780134753119_smallCoverImage.gif)
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
![A First Course in Probability](https://www.bartleby.com/isbn_cover_images/9780321794772/9780321794772_smallCoverImage.gif)
![A First Course in Probability (10th Edition)](https://www.bartleby.com/isbn_cover_images/9780134753119/9780134753119_smallCoverImage.gif)
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
![A First Course in Probability](https://www.bartleby.com/isbn_cover_images/9780321794772/9780321794772_smallCoverImage.gif)