Let y = 3 H -3 -2 and u = projuy = 2 1 (a) Find the orthogonal projection of y onto u. H (b) Compute the distance d from y to the line through u and the origin. d=

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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### Linear Algebra Problem: Orthogonal Projection and Distance Calculation

Given the vectors:
\[ \mathbf{y} = \begin{bmatrix} 3 \\ -2 \\ -3 \end{bmatrix} \quad \text{and} \quad \mathbf{u} = \begin{bmatrix} 2 \\ 1 \\ -1 \end{bmatrix} \]

(a) **Find the orthogonal projection of \(\mathbf{y}\) onto \(\mathbf{u}\).**
\[ \text{proj}_{\mathbf{u}}\mathbf{y} = \begin{bmatrix}
\boxed{} \\ \boxed{} \\ \boxed{}
\end{bmatrix} \]

(b) **Compute the distance \(d\) from \(\mathbf{y}\) to the line through \(\mathbf{u}\) and the origin.**
\[ d = \boxed{} \]
Transcribed Image Text:### Linear Algebra Problem: Orthogonal Projection and Distance Calculation Given the vectors: \[ \mathbf{y} = \begin{bmatrix} 3 \\ -2 \\ -3 \end{bmatrix} \quad \text{and} \quad \mathbf{u} = \begin{bmatrix} 2 \\ 1 \\ -1 \end{bmatrix} \] (a) **Find the orthogonal projection of \(\mathbf{y}\) onto \(\mathbf{u}\).** \[ \text{proj}_{\mathbf{u}}\mathbf{y} = \begin{bmatrix} \boxed{} \\ \boxed{} \\ \boxed{} \end{bmatrix} \] (b) **Compute the distance \(d\) from \(\mathbf{y}\) to the line through \(\mathbf{u}\) and the origin.** \[ d = \boxed{} \]
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