Let {xn} be a sequence of real numbers. Let yn be the average of the first n-terms: x1+ x2 + Yn + Xn n Prove that if {Xn} converges to x, then {Yn} also converges to xo. (Hint: using the definition of convergence, choose a large threshold N after which |xn – x| is as small as we want, then choose n large enough such that the |x; – x|/n is very small for 1 < i< N.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Let {xn} be a sequence of real numbers. Let yn be the average of the first
n-terms:
X1 + x2 +
+ Xn
Yn
n
Prove that if {xn} converges to xo, then {yn} also converges to xo. (Hint: using
the definition of convergence, choose a large threshold N after which |Xn – x∞| is as small as
we want, then choose n large enough such that the |x; – x|/n is very small for 1 < i < N.)
Consider a numerical series 1 an. Denote by sn =
of the first n-partial sums be
Lk=1 ak the partial sums. Let the average
S1 + 82 +
+ Sn
On =
As a direct corollary of part a), the convergence of {Sn} implies that of {on}. In the following
problems, we explore when the convergence of {on} implies that of {sn}.
If {on} converges to o, and ak = o() as k → 0 (ak is “small Oh" of ), prove that
{Sn} also converges to o. (Hint: express the difference Sn-On using {kak : k = 1, · ·. ,n}.)
as k → o (ak is “big Oh" of
If {on} converges to oo, and ak =
), prove that {sn} also converges to ooo
()o
Transcribed Image Text:Let {xn} be a sequence of real numbers. Let yn be the average of the first n-terms: X1 + x2 + + Xn Yn n Prove that if {xn} converges to xo, then {yn} also converges to xo. (Hint: using the definition of convergence, choose a large threshold N after which |Xn – x∞| is as small as we want, then choose n large enough such that the |x; – x|/n is very small for 1 < i < N.) Consider a numerical series 1 an. Denote by sn = of the first n-partial sums be Lk=1 ak the partial sums. Let the average S1 + 82 + + Sn On = As a direct corollary of part a), the convergence of {Sn} implies that of {on}. In the following problems, we explore when the convergence of {on} implies that of {sn}. If {on} converges to o, and ak = o() as k → 0 (ak is “small Oh" of ), prove that {Sn} also converges to o. (Hint: express the difference Sn-On using {kak : k = 1, · ·. ,n}.) as k → o (ak is “big Oh" of If {on} converges to oo, and ak = ), prove that {sn} also converges to ooo ()o
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