Let (x4/3y5/3 + ix5/3y4/3)/(x² + y²) if z 0, if z = 0. f(z): >= {(x²4/ :{ 0 Show that the Cauchy-Riemann equations hold at z = 0 but that f is not differen- tiable at this point. [HINT: Consider the difference quotient f(Az)/Az for Az → 0 along the real axis and along the line y = x.]

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