Let x1 = 1 and define xk+1 = sqrt(2xk) where k is a natural number. Prove that the sequence {xk} for k = 1 to infinity converges and find its limit.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
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Let x1 = 1 and define xk+1 = sqrt(2xk) where k is a natural number. Prove that the sequence {xk} for k = 1 to infinity converges and find its limit.

Expert Solution
Step 1

Given: x1=1, xk+1=2xk

So, x2=2x1=2>x1

x3=2x2=22>x2

On generalizing, we get 

x1<x2<x3.....<xk

So, sequence xk is an increasing sequence and hence monotonic

Also, 1xk<2 k

So, xk is bounded 

As the sequence xk is monotonic as well as bounded . So, by Monotone Convergence Theorem it must be convergent.

That is , xk is convergent.

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