Let X,, X2, . .. , X, represent a random sample from a Rayleigh distribution with the following pdf. f(x; 0) x > 0 (a) Determine the maximum likelihood estimator of 0. (Ex,?) / n (ΣΧ) / 2η x/ 2n (Ex,?) / 2n Calculate the estimate from the following n = 10 observations on vibratory stress of a turbine blade under specit conditions. (Round your answer to three decimal places.) 17.67 8.71 9.14 16.47 17.69 5.69 5.28 14.56 6.21 5.81 (b) Determine the mle of the median of the vibratory stress distribution. [Hint: First express the median in term 0.] o (1.38636) O 1.3863ô 1.38636 O (1.38636) 1.38630

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
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Chapter4: Writing Linear Equations
Section: Chapter Questions
Problem 12CR
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Let X1, X2 .
, X, represent a random sample from a Rayleigh distribution with the following pdf.
n
f(x; 0)
/(20)
x > 0
(a) Determine the maximum likelihood estimator of 0.
(Ex,?) / n
x/ n
(EX;) / 2n
x/ 2n
O (Ex,?) / 2n
Calculate the estimate from the following n = 10 observations on vibratory stress of a turbine blade under specified
conditions. (Round your answer to three decimal places.)
17.67
8.71
9.14
16.47
17.69
5.69
5.28
14.56
6.21
5.81
(b) Determine the mle of the median of the vibratory stress distribution. [Hint: First express the median in terms of
0.]
o (1.38636)
O 1.3863ô
1.38630
38630
1.38630
Transcribed Image Text:Let X1, X2 . , X, represent a random sample from a Rayleigh distribution with the following pdf. n f(x; 0) /(20) x > 0 (a) Determine the maximum likelihood estimator of 0. (Ex,?) / n x/ n (EX;) / 2n x/ 2n O (Ex,?) / 2n Calculate the estimate from the following n = 10 observations on vibratory stress of a turbine blade under specified conditions. (Round your answer to three decimal places.) 17.67 8.71 9.14 16.47 17.69 5.69 5.28 14.56 6.21 5.81 (b) Determine the mle of the median of the vibratory stress distribution. [Hint: First express the median in terms of 0.] o (1.38636) O 1.3863ô 1.38630 38630 1.38630
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